They did not add the problems right it was 12,090.37
Answer:
a 0.5
b 0.4831
c 0.4354 < P < 0.53008
Step-by-step explanation:
Given that :
Probability (P) of a head or a tail when a coin is being tossed or flipped = 1/2 = 0.5
Sample size (n) = 296
Selected sample (X) = 143
a) Given that Emily used a coin toss to select either her right hand or her left hand, what proportion of correct responses would be expected if the touch therapists made random guesses?
The proportion of correct responses that would be expected if the touch therapists made random guesses is 0.5
b) Using Emily's sample results, what is the best point estimate of the therapists' success rate?
Point estimate 
= 
= 0.4831
c) Using Emily's sample results, construct a 90% confidence interval estimate of the proportion of correct responses made by touch therapists.
The
for 90% is 1.645
Using the formula P" -E < P < P" + E
where E = margin of error : 



= 0.0477
∴ P" -E < P < P" + E
= 0.4831 - 0.0477 < P < 0.4831 + 0.0477
= 0.4354 < P < 0.53008
Answer: A, If it is Tuesday, Marla has a piano lesson.
B. is implying that they don’t cancel any lesson at all for any reason
C. is implying that they cannot reschedule a lesson for a different day
D. is implying that Marla cannot play piano at all unless it is for a lesson
Adding the equations to eliminate p would be the correct step because when you add the equations together, the variable p would cancel out and be eliminated leaving you with 2w=35 you can then solve for the value of w which you can then input to find the value of p, allowing you to solve for the values of both p and w.