I looked it up, and it said false.
Answer:
C) P (X2 ≤ 8.2) = 0.96
Step-by-step explanation:
P value for the test is the probability of obtaining results that have been observed in the null hypothesis statement. A very small value of p indicates that there is unlikely chance of null hypothesis being true which means that we cannot accept null hypothesis based on the small p value.
(2/5)+(3/(5x))=(x+5)/10
nasty fractions, we hates it forever
so
get rid of all those nasty fractions
multiply both sides by 10x
4x+6=x(x+5)
distribute
4x+6=x^2+5x
minus (4x+6) from both sides
0=x^2+x-6
factor
0=(x-2)(x+3)
set each to zero
0=x-2
2=x
0=x+3
-3=x
x=-3 and 2
3rd option is answer
Answer:
i. terms = 5xy(z)^2 , -3zy
coefficient = 5 and -3
ii. terms = 1 , X ,x^2
coefficient = 1 , 1
iv. terms = 3 , -pq , qr, -rp
coefficient = -1 ,1 , -1
v. terms = X/2 , y/2 , -xy
coefficient= 1/2 ,1/2 and -1
