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3 years ago

5

Abundance is a car salesman. He earns $250 for every car he sells plus 3% commission. If Abundance sells 2 cars in one week for

a total of 54,624.00, what are his total earnings for the week?

1 answer:

grin007 [14]3 years ago

3 0

Answer:

1,278 for one day so for the week - 6,132

Step-by-step explanation:

You might be interested in

Given the sequence below, and that sequence has a domain of n 2 1, find the fifth

solmaris [256]

The fifth term of f(n) = n² - 3 is 22

$\texttt{ }$

<h3>Further explanation</h3>

Firstly , let us learn about types of sequence in mathematics.

Arithmetic Progression is a sequence of numbers in which each of adjacent numbers have a constant difference.

$\boxed{T_n = a + (n-1)d}$

$\boxed{S_n = \frac{1}{2}n ( 2a + (n-1)d )}$

<em>Tn = n-th term of the sequence</em>

<em>Sn = sum of the first n numbers of the sequence</em>

<em>a = the initial term of the sequence</em>

<em>d = common difference between adjacent numbers</em>

$\texttt{ }$

Geometric Progression is a sequence of numbers in which each of adjacent numbers have a constant ration.

$\boxed{T_n = a ~ r^{n-1}}$

$\boxed{S_n = \frac{a( 1 - r^n ) }{1 - r}}$

<em>Tn = n-th term of the sequence</em>

<em>Sn = sum of the first n numbers of the sequence</em>

<em>a = the initial term of the sequence</em>

<em>r = common ratio between adjacent numbers</em>

Let us now tackle the problem!

$\texttt{ }$

<u>Given:</u>

f(n) = n² - 3

<u>Asked:</u>

f(5) = ?

<u>Solution:</u>

$\texttt{for } n \geq 1 :$

$f(n) = n^2 - 3$

$f(5) = 5^2 - 3$

$f(5) = 25 - 3$

$f(5) = \boxed{22}$

$\texttt{ }$

<h3>Learn more</h3>

Geometric Series : brainly.com/question/4520950
Arithmetic Progression : brainly.com/question/2966265
Geometric Sequence : brainly.com/question/2166405

<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Arithmetic and Geometric Series

Keywords: Arithmetic , Geometric , Series , Sequence , Difference , Term

7 0

4 years ago

Shenelle has 100100100 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of th

cluponka [151]

Area as a function of width, w is:
a(w)=(w-25)^2+625
for maximum area, the width will be:
a'(w)=2(w-25)+0=0
solving for w we egt
2w-50=0
2w=50
w=25 m
given that the perimeter is 100, the length will be:
100=2(L+W)
solving for L we get:
L=50-W
but W=25m
hence
L=50-25=25 m
thus the maximum area will be:
A=L*W=25*25=625m^2

8 0

3 years ago

Read 2 more answers

I'm pretty sure I got something wrong in this assignment can someone see where it went down? Instructions included.

baherus [9]

Answer:

The 12 4/9 in the bottom right corner is 13 7/9 and the 8 two squares to the left of it is 6 2/3.

Step-by-step explanation:

You actually did really well! It was only in the last two squares that you went wrong. The first wrong one was just the 12 4/9 in the last column and second to last row, which should be 13 7/9. Then with that the last square that is wrong is just the 8 in the 5th column and second to last row, which should be 6 2/3. Those are the only ones so you actually did really well, great job!

Hope this helped!

4 0

3 years ago

4 students of 20 students

Harlamova29_29 [7]

5 groups of 4 students = 20 students????????????????

8 0

3 years ago

Is it correct?????<br> ????<br> ??

zlopas [31]

Answer:

1 is a

2 is b

Hope that helps!!! tysm!! :3

6 0

4 years ago

Read 2 more answers