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2 years ago

I dont understand this

Mathematics

1 answer:

vladimir1956 [14]2 years ago

4 0

N = 40
Dmdndndkfkdkdkxxkkddkfkfkfkfkfkf

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Kathy’s customer base is 2/3 residential and 1/3 business if she has 350 residential customers how many total customers does she

Scorpion4ik [409]

If we made it into a ratio of residential customers to business customers, it would be a 2:1

350/2 = 175

350 + 175 = 525

525 total customers

4 0

2 years ago

Pls help meeee I don’t understand this at alll

balu736 [363]

Answer:

you need the formula for the cone , Korc

Step-by-step explanation:

formula for cone = $\frac{1}{3}$ *π* $r^{2}$ *h

they tell us that the diameter is 8 so r = 4

and that h = 9

volume of cone = $\frac{1}{3}$ *π* $4^{2}$ *9

VoC = 150.796

VoC = 150.8 ( to the nearest 10th)

5 0

3 years ago

Given A(5, –2), what are the coordinates of (T⟨−3, 4⟩∘ Rx-axis)(A)?

Bad White [126]

Answer:

not sure

Step-by-step explanation:

7 0

2 years ago

Use the set of data to answer the question.

Sindrei [870]

The median is the 6 th element of the 11 th
that is 7

7 0

2 years ago

If cos theta= -8/17 and theta is in quadrant 3, what is cos2 theta and tan2 theta

Karo-lina-s [1.5K]

$\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad 
\begin{array}{llll}
\textit{now, hypotenuse is always positive}\\
\textit{since it's just the radius}
\end{array}
\\\\\\
thus\qquad cos(\theta)=\cfrac{-8}{17}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}$

since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side

now, let us use the pythagorean theorem, to find the opposite side, or "b"

$\bf c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite
\end{cases}
\\\\\\
\pm\sqrt{17^2-(-8)^2}=b\implies \pm\sqrt{225}=b\implies \pm 15=b$

so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means, -15 = b

so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
\boxed{1-2sin^2(\theta)}\\
2cos^2(\theta)-1
\end{cases}
\\ \quad \\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-----------------------------\\\\
cos(2\theta)=1-2sin^2(\theta)\implies cos(2\theta)=1-2\left( \cfrac{-15}{17} \right)^2
\\\\\\
cos(2\theta)=1-\cfrac{450}{289}\implies cos(2\theta)=-\cfrac{161}{289}$

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\left( \frac{-15}{-8} \right)}{1-\left( \frac{-15}{-8} \right)^2}
\\\\\\
tan(2\theta)=\cfrac{\frac{15}{4}}{1-\frac{225}{64}}\implies tan(2\theta)=\cfrac{\frac{15}{4}}{-\frac{161}{64}}
\\\\\\
tan(2\theta)=\cfrac{15}{4}\cdot \cfrac{-64}{161}\implies tan(2\theta)=-\cfrac{240}{161}$

6 0

2 years ago

I dont understand this​

I dont understand this