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tamaranim1 [39]
1 year ago
14

Divide and simplify. √36 x⁴ / √9 x⁶

Mathematics
1 answer:
Vikki [24]1 year ago
7 0

The divide and simplify of the equation √36 x⁴ / √9 x⁶ will result to  \frac{2}{x^{2} }

Let's begin by simplifying the equation;

Simplify the equation by finding the square root of both 36 and 9

The square root of 36= 6

The square root of 9= 3

= \frac{6x^{4} }{3x^{6} }

The above equation can also be written as;

=  6x^{4}  * 3x^{-6}

The next step is to solve the powers, that is,

=   \frac{6x^{4} }{3x^{6} }

Cancel out 6 by 3 and get  2

The result is,  

=  \frac{2}{x^{6-4} }

The final submission result is,

=  \frac{2}{x^{2} }

To find more on divide and simplify, go to: brainly.com/question/16356152

#SPJ4  

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Find the condition that one root of the quadratic equation may be 1 more than the other.
Eddi Din [679]
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
4 0
3 years ago
What is the value of the expression below when a = 3 and b = 7?
svp [43]

Answer:

42

Step-by-step explanation:

9^2*7-2*7

56-14

42

I hope this helps.

6 0
3 years ago
Read 2 more answers
Which table of values includes solutions to the function f(x) = -2x^2?
olga_2 [115]
The table could include values like this:
x     y
-2   -8
-1   -2
0    0
1    -2
2    -8
3 0
3 years ago
The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

Using the normal distribution, it is found that the probabilities are given as follows:

a) 0.8871 = 88.71%.

b) 0.0778 = 7.78%.

c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1250 - 1140}{77.5}

Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

1 - 0.9222 = 0.0778 = 7.78%.

Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

Z = \frac{X - \mu}{s}

Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
If a and b are two angles in standard position in Quadrant I, find cos(a-b) for the given function values. sin a=3/5and cos b=12
goldfiish [28.3K]

The identity in question is

cos(a - b) = cos(a) cos(b) + sin(a) sin(b)

so that

cos(a - b) = 12/37 cos(a) + 3/5 sin(b)

Since both a and b lie in the first quadrant, both cos(a) and sin(b) will be positive. Then it follows from the Pythagorean identity,

cos²(x) + sin²(x) = 1,

that

cos(a) = √(1 - sin²(a)) = 4/5

and

sin(b) = √(1 - cos²(b)) = 35/37

So,

cos(a - b) = 12/37 • 4/5 + 3/5 • 35/37 = 153/185

7 0
2 years ago
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