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Nastasia [14]
3 years ago
11

Estimate the square root of 78

Mathematics
2 answers:
Dima020 [189]3 years ago
8 0

Answer:

8.83176

Step-by-step explanation:

Furkat [3]3 years ago
5 0

Answer:

8.83176

Step-by-step explanation:

The square root of 78 is 8.83176, or 8.832 (rounded to the nearest thousandth).

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Pls help i will give 5 starts and brainliest question is down below 9:22
OleMash [197]

4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.

5) B

Area of a triangle = ½ bh.

where b = base &

h = height.

Area of outer shape = (½ x 16 x 12) in^2.

= 96 in^2.

Area of unshaded inner shape = (½ x 3 x 4) in^2.

= 6 in^2.

Area of shaded region = (96 – 6) in^2.

= 90 in^2.

4 0
2 years ago
The following patterns are made using small squares
Alex787 [66]

Answer:

stuck on that too

Step-by-step explanation:

I use mathswatch aswell

5 0
3 years ago
Enter the solution (x,y) to the system of equations shown.<br> y= -6<br> y= 4x+12
andriy [413]
Y= -6 --> plug this -6 into the y of the 2nd equation
y= 4x+12 --> -6 = 4x+12 --> 4x = -18
x = -18/4 = -9/2 --> now this is the x solution coordinate, and we know that y must equal -6 from the 1st equation, so our solution point is:
(-9/2, -6)
Hope that helped!
6 0
3 years ago
Read 2 more answers
B is the midpoint of AC. AB = 2x+12 and BC = 5x + 10. Find AC
3241004551 [841]

Answer:

x=6

Step-by-step explanation:

/AB/=2x+12

/BC/=5x+10

3x+2=5x-10 subtract 2 from both sides

3x=5x-12 subtract 5x from both sides

-2x=-12 divide both sides by -2x

x =6

5 0
2 years ago
Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two dice. players win
Ivahew [28]

The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.

In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.

So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Similarly,

P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

7 0
3 years ago
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