18
I used a calculator so you’ll need someone else to explain my apologies. I’m tried but I wanted to try and help by giving you the answer
1. Set up the long addition.
2 4 7
+3 5 8
_______
2. Calculate 7+8, which is 15.
since 15 is two-digit, we carry the first digit 1 to the next column.
1
2 4 7
+ 3 5 8
________
5
3. Calculate 4+5, which is 9. Now add the carry digit of 1, which is 10. Since 10 is two-digit, we carry the first digit 1 to the next column.
1 1
2 4 7
+ 3 5 8
________
0 5
4. Calculate 2+3, which is 5. Now add the carry digit of 1, which is 6.
1 1
2 4 7
+3 5 8
______
6 0 5
5. Therefore, 247 + 358 = 605.
605
The area of the triangle is
A = (xy)/2
Also,
sqrt(x^2 + y^2) = 19
We solve this for y.
x^2 + y^2 = 361
y^2 = 361 - x^2
y = sqrt(361 - x^2)
Now we substitute this expression for y in the area equation.
A = (1/2)(x)(sqrt(361 - x^2))
A = (1/2)(x)(361 - x^2)^(1/2)
We take the derivative of A with respect to x.
dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]
dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]
Now we set the derivative equal to zero.
(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0
-2x^2 + 361 = 0
-2x^2 = -361
2x^2 = 361
x^2 = 361/2
x = 19/sqrt(2)
x^2 + y^2 = 361
(19/sqrt(2))^2 + y^2 = 361
361/2 + y^2 = 361
y^2 = 361/2
y = 19/sqrt(2)
We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
Answer: Its 4
Step-by-step explanation:
- Okay so 2+2 is just saying like your adding 1+1+1+1 and that gives you four.
- They're is another way you can get the sum too, You just add 2 to the number 2.
