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3 years ago

Which two conditions would result in the strongest electric force between charged objects?

Mathematics

2 answers:

Fudgin [204]3 years ago

8 0

Answer: C and D

Step-by-step explanation:

Nostrana [21]3 years ago

4 0

Answer:

B and C

Step-by-step explanation:

if it wants one of those it's B, but the charge of the objects should be balanced and conductors allow the current to flow through them, C adds to that by drawing the charges closer together to result in a stronger bond and current transference

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aimi is making a valentines day cards for everyone in her class. she plans to use a whole sheet of paper for each of her 6 close

Luba_88 [7]

You have to subtract the 6 first and then divide the rest by 1/8.
34-6=28
28×1/8=224

6 0

4 years ago

Study island Jack Russell high school 96 students plan on going to end in State College and 58 students plan on going to an out

Daniel [21]

Answer:

48:29

Step-by-step explanation:

So lets find the ratio without simplest form: the ratio is 96:58

When writing the ratio we write the one mention first

Now lets write it in simplest form practically reducing it to its lowest term

$\frac{96}{58}$ ( we first write it as a fraction)

$\frac{96}{58}$ ÷ $\frac{2}{2}$ =48:29

So the answer is 48:29

HOPE IT HELPED

3 0

3 years ago

company loses $5,400 as the result of a manufacturing defect. Each of the 8 owners have agreed to pay an equal amount, x, to pay

Alisiya [41]

Answer:

Step-by-step explanation:

5400 / 8 = x

675 = x

Each owner pays 675

8 0

2 years ago

the perimeter of one rectangle is 120cm. another rectangle with twice the length amd and one third the width has a perimeter of

fgiga [73]

Answer:

Dimensions of 1st rectangle,

length = 39 cm, width = 21 cm.

Dimensions of the 2nd rectangle,

length = 78 cm, width = 7 cm.

Step-by-step explanation:

Let the dimensions of the 1st rectangle be,

Length = x, width = y

so the dimensions of the 2nd rectangle becomes,

Length = 2x, width = y/3

perimeter of the first rectangle,

2(x+y)=120 --------- (i)

perimeter of the 2nd rectangle,

2(2x+y/3)=170 ---------(ii)

if we solve equation (i) and (ii), we'll get,

x = 39

y = 21

for the other rectangle, 2x = 78, y/3 = 7.

Answered by GAUTHMATH

3 0

3 years ago

Factorize: Challenge problem:<br> x^2+19x+78<br> help :)

Trava [24]

Answer:

(x + 6)(x + 13)

Step-by-step explanation:

Given

x² + 19x + 78

Consider the factors of the constant term (+ 78) whuch sum to give the coefficient of the x- term (+ 19)

The factors are + 6 and + 13 , since

6 ×13 = + 78 and 6 + 13 = + 19 , then

x² + 19x + 78 = (x + 6)(x + 13) ← in factored form

3 0

3 years ago

Read 2 more answers