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Softa [21]
3 years ago
11

How many electrons are in mg2+?

Mathematics
1 answer:
Oxana [17]3 years ago
7 0
(Pay attention to the subject you're choosing, this is supposed to be in the Chemistry section, not here in the Mathematics)
On the periodic table, the Magnesium Mg is located in period 3, group 2. So it got 12 electrons.
So to become the cation Mg2+, the Magnesium has lost 2 electrons during it's formation.
So 12-2=10.
So there's 10 electrons in the Cation magnesium Mg2+

Hope this Helps! :)
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3 years ago
Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.
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A regular hexahedron is actually a cube. 

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
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Volume of a cube with side a is: V = a³
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We have:
D = 8√2 in

V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}
8 0
3 years ago
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