Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
C. 5.8 × 
Step-by-step explanation:
0.000058
4 zeros
4 + 1 = 5
5.8 × 10⁻5
The answer is 588 because if you multiply 6.75 percent of 4800 by 13, and then subtract it from 4800, you get 588.
C because if the denominator equals x-2 that means that the horizontal asymptote happens at x=2. And because the numerator and denominator have the same degree then you divide leading coefficients to get the vertical asymptote at y=-2
Answer: m=1/30n+29/15
Step-by-step explanation:
