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MA_775_DIABLO [31]
2 years ago
8

Can you guys help me solve this equation with step-by-step help, please...

Mathematics
1 answer:
Alex2 years ago
4 0

Step-by-step explanation:

-2x - 5y = 16___(1)

2x - 3y = -16___(2)

(1) + (2) ==> -2x -5y = 16

(+) <u>2x -3y = -16</u>

-8y = 0

y = 0/-8

y = 0

y=0 in (1)

(1)---> -2x-5y =16

-2x - 5(0) = 16

-2x - 0 = 16

-2x = 16

x = 16/-2

x = -8

x = -8 , y = 0

-5x + 2y = 11__(1) ; -3x + 4y = -13___(2)

multiply eqn(1) with 2

2 × (1) : -10x + 4y = 22___(3)

(3) - (2) :. -10x + 4y = 22

(-) <u>-3x </u><u>+</u><u> </u><u>4</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>1</u><u>3</u>

-7x = 35

x = 35/-7

x = -5

x=-5 in (1)

(1) : -5x + 2y = 11

-5(-5) + 2y = 11

25 + 2y = 11

2y = 11 - 25

2y = -14

y = -14/2

y = -7

x = -5 , y = -7

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Step-by-step explanation:

The given equation for the line is 4·x + 2·y = 8

a) The coordinates of P = P(0, _)

Therefore, the point 'P', which is the point where the variable y = 0, is the point the (straight line) graph intercepts the x-axis (the x-intercept)

When y = 0 from the given equation, we get;

4·x + 2·y = 8

At the point y = 0;

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∴ The coordinates of P = P(0, _) = P(0, <u>2</u>)

Similarly, when x = 0, we get;

4·x + 2·y = 8

At the point x = 0;

4 × 0 + 2·y = 8

y = 8/2 = 4

y = 4

∴ The coordinates of Q = Q(_, 0) = Q(<u>4</u>, 0)

b) Rewriting the given equation in terms of 'y' gives;

y = (8 - 4·x)/2 = 4 - 2·x

y = 4 - 2·x

With the help of MS Excel, the points P and Q are plotted in the attached graph

c) The line of the graph of the function 4·x + 2·y = 8 for values of x from -2 to 3 can be added by Changing the Chart Type to 'Scatter with Smooth Lines and Markers' within MS Excel as presented in the included graph of the line.

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