Answer:
Step-by-step explanation:
Pythagoras Theroem.
Leg₁²+leg₂²=hypotenuse²
Data:
Leg₁=48
hypotneuse=80
(48)²+ leg₂²=(80)²
2304+leg₂²=6400
leg₂²=6400-2304
leg₂²=4096
leg₂=√4096
leg₂=64
Answer: B. 64
Polynomial 1 : x²-x²+4x -2+1 = 4x -1
Polynomial 2 : 3x-x-2x²-2+1 = -2x²+2x-1
Polynomial 3 : 4 -2x+x-x²+x²-x² = -x²-x+4
According to the question,
Polynomial 1+Polynomial2+Polynomial3 + Polynomial4 = 6x
=> 4x -1+ (-2x²+2x-1) +(-x²-x+4) + Polynomial4= 6x
=> -3x²-x+2+Polynomial4= 0
<h2>=> 3x²+x -2= Polynomial4</h2>
OPTION B
Answer:
x≠-12; x≠0
Step-by-step explanation:
A fraction denominator cannot be 0.
3x(x+12)≠0
if you multiply a number by zero, the product is also zero
3x≠0
x≠0
x+12≠0
x≠-12
I was taught that if you must simplify a square root by doing the birthday cake method. Basically divide the radical by its lowest common factor until it can't be divided anymore. Also the lowest factor can't be 1. For 27, the lower common factor is 3.
27/3 = 9/3 = 3
Since in a common square root the index is 2, you must pair the least common factors. There is 1 pair of 3 and there is 1 remaining

is 3

.
You must multiply 3 and 8, which gives 24
The answer is 24