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VladimirAG [237]
2 years ago
14

Calculus: Help ASAP

Mathematics
1 answer:
Serggg [28]2 years ago
5 0
\bf \displaystyle \int\limits_{-1}^{0}~(4x^6+2x)^3(12x^5+1)\cdot  dx\\\\
-------------------------------\\\\
u=4x^6+2x\implies \cfrac{du}{dx}=24x^5+2\implies \cfrac{du}{2(12x^5+1)}=dx\\\\
-------------------------------\\\\
\displaystyle \int\limits_{-1}^{0}~u^3\underline{(12x^5+1)}\cdot\cfrac{du}{2\underline{(12x^5+1)}}\implies \cfrac{1}{2}\int\limits_{-1}^{0}~u^3\cdot du\\\\
-------------------------------\\\\

\bf \textit{now, we'll change the bounds, using u(x)}
\\\\\\
u(-1)=4(-1)^6+2(-1)\implies u(-1)=2
\\\\\\
u(0)=4(0)^6+2()\implies u(0)=0\\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{2}^{0}~u^3\cdot du\implies \left. \cfrac{1}{2}\cdot \cfrac{u^4}{4}  \right]_{2}^{0}\implies \left. \cfrac{u^4}{8}  \right]_{2}^{0}\implies [0]-[2]\implies -2
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SpyIntel [72]

Answer:

x = 3 ± \sqrt{24}

or

x = 3 + \sqrt{24}, x = 3 - \sqrt{24}

Step-by-step explanation:

given f(x) = 2(x - 3)^2 - 8, find when f(x) = 40

So, we plug in 40 for f(x) in the 1st equation and solve for x.  (Aim to got x on its own)

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-----------------------------

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5 0
2 years ago
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nirvana33 [79]

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