3 years ago

What is the solution?

Mathematics

2 answers:

torisob [31]3 years ago

8 0

Answer:

$(0,1)$

HACTEHA [7]3 years ago

6 0

(0,1) hope I helped and btw count by the squares and could I get brainliest

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The sum of two numbers is 150 and the ratio of the same two numbers is 3 to 2 . find the bigger number

krek1111 [17]

Ratio- 3: 2

3x + 2x = 150
5x = 150
x = 30

3x is the larger number so plug in the x value with 30.

3x
3 x 30
90

The larger number is 90.

Hope I helped.. ^^

8 0

3 years ago

Read 2 more answers

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$