Answer:
See Explanation
Step-by-step explanation:
Line l is bisector of MO... (given)
Thus Proved
The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
Simple you just solve for y and put the equation in slope-intercept form
I would say 1/12 ft but I might be wrong.
Answer:
38c + 5
Step-by-step explanation:
8c x 2 x 2 - c + 3 + 2c x 2 x 2 - c + 2
38c +5