Consider the series 4+8+16+32+... What is the common ratio?

Answer all the questions:

nata0808 [166]

Answer:

Step-by-step explanation:

nmndndacanadakdndjqnjqenedjqdnqednaansndwenfqwndca

4 0

3 years ago

Let A fa, b,c. B [a, b, d), and C tb, d,e. Find the union of A and B, and then the union of this with C. Also, find the union of

Andre45 [30]

Answer: A ∪ B = {a, b, c, d}

(A ∪ B) ∪ C = = {a, b, c, d, e}

B ∪ C = = {a, b, d, e}

(B ∪ C) ∪ A = = {a, b, c, d, e}

Step-by-step explanation:

A = {a, b, c} B = {a, b, d} C = {b, d, e}

Union means "to join" so combine the sets to form a union.

A ∪ B = {A & B}

= {a, b, c & a, b, d}

= {a, b, c, d} because we do not need to list a & b twice

(A ∪ B) ∪ C = {(A ∪ B) & C)

= {a, b, c, d & b, d, e}

= {a, b, c, d, e} because we do not need to list b & d twice

B ∪ C = {A & B}

= {a, b, d & b, d, e}

= {a, b, d, e} because we do not need to list b & d twice

(B ∪ C) ∪ A = {(B ∪ C) & A)

= {a, b, d, e & a, b, c}

= {a, b, c, d, e} because we do not need to list a & b twice

4 0

3 years ago

From the set {1, 3, 4}, use substitution to determine which value of x makes the equation true.

Harlamova29_29 [7]

30 - 2x= 22

-2x = 22 - 30

-2x = -8

(dived both sides by -2)

x= 4

8 0

2 years ago

PLZ 50 POINTS please answer question below

katrin2010 [14]

Volume=length*width*height (for a rectangular prism)

Plug in the values.

4 1/4*3*1 1/4= the volume

4 1/4*3= 12 3/4, so:

12 3/4 * 1 1/4 is correct as well.

The answer you checked is the correct answer.

I hope this helps!
~kaikers

5 0

3 years ago

Read 2 more answers

A local swim club offers competitive meets throughout the season. Some races are open competitions with no qualifying times. Oth

sammy [17]

Answer:

The first option is correct.

The group competing in the open competitions is most likely to have a higher standard deviation than the group competing in the qualified competitions.

Step-by-step explanation:

The standard deviation of a dataset measures how the dataset spreads round a particular average value.

For the qualified competitions, there's a standing rule that only 15-16 year olds that post swimming times of 1 minute 8 seconds or less in the 100 m swimming race can participate in this competition. This means, all the participants of this particular competition are good swimmers relatively and the spread of their resulting swimming times should be just around the 1 minute and 8 second. If there will be outliers, it'll be a very few one.

Therefore, the standard deviation of their swimming times will not be so large as all the data focuses around 1 minute and 8 seconds.

But in the open competition, everyone can participate. It is open to skilled, unskilled, fast, slow, shy, brave, basically all types of swimmers. And with this diverse talent pool comes the large variation in swimming times. Plenty unskilled and slow people will post swimming times that are way more than 1 minute & 8 seconds, some few good ones will post numbers that are good enough and close to 1 minute, 8 seconds. At the end of the day, the large variation in swimming times across the talent spectrum leads to a large standard deviation.

So, the group competing in the open competitions is most likely to have a higher standard deviation than the group competing in the qualified competitions.

Only if not too many people participate in eirher of the competitions can this reasoning be faulty.

8 0

3 years ago