Answer:B) Archives/backups
Explanation: Archive is the group of records of data that are saved for the future use.These are the historic data that is not currently used in the actual location .
Backup is the the the copy of the group of data that is not in the original form to be used in future. Thus the correct option is option(B).
Updating of the plans by the technician cannot be done through other given options because they don't hold the historic records of the data for the renewing of the plans.
It is under the drawings group.
Answer:
(c) system.exist(1);
Explanation:
system.exist(1); is used for the termination of the program here both option c and d should be correct but in option d there is exit(0) and zero indicates return means program will return but besides zero if there is any non zero number then program will not return and in option c there is a non zero number which means program will not return so option c system.exist(1); will be the correct option for the termination of program
Answer:
Co-branding.
Explanation:
Around the world, various brands of personal computers are sold with Pentium processors. This fact is often used as a selling point, with advertising that proclaims "Intel Inside." Co-branding concept do such advertising.
Answer:
- food_category = {
- "Fruits": ["Apple", "Strawberries", "Orange"],
- "Vegetables": ["Carrots", "Peas", "Onions"],
- "Meats": ["Chicken", "Beef", "Mutton"]
- }
-
- for cat in food_category:
- output = cat + ": "
- for food in food_category[cat]:
- output += food + ", "
- print(output)
-
- answer = input("Do you want to add category or food (Y - Yes N - No): ")
-
- while(answer == "Y"):
- choice = input("New Category (N) or New Food (nf): ")
-
- if(choice == "N"):
- new_cat = input("Enter new category name: ")
- if(new_cat not in food_category):
- food_category[new_cat] = ""
- elif(choice == "nf"):
- cat = input("Enter category: ")
- new_food = input("Enter new food name: ")
- food_category[cat].append(new_food)
-
- answer = input("Do you want to add new category or food (Y - Yes N - No): ")
-
- print("All food categories: ")
- for cat in food_category:
- print(cat)
-
- selected_cat = input("Select a category to view the food list: ")
- output = ""
- for food in food_category[selected_cat]:
- output += food + ", "
- print(output)
Explanation:
The solution code is written in Python 3.
Firstly, create a food category dictionary data structure (Line 1 -5). Next, display all the food category and the food in each category (Line 7 - 11)
Next prompt user to feedback if they wish to add new category or new food (Line 13).
While the answer is yes prompt user to enter their choice, either category or food and use if else if statements to handle the choice made by the user. If the choice is new category, prompt user to enter new category name and check if the new category is already exist in the dictionary. If not, add that category to dictionary (Line 18 - 21).
If the choice is food, nf, prompt user to input food category and enter the new food name and add it to the food_category list (Line 22 - 25).
After that prompt user to enter if they wish to continue to add new data (Line 27).
After collecting all info from user, write a for loop to display all the categories (Line 29 - 31).
At last, prompt user to select a category and display all the food of the selected category (Line 33 - 37).
