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Answer:
Option d) B is 1.33 times faster than A
Given:
Clock time,
No. of cycles per instructions,
Solution:
Let I be the no. of instructions for the program.
CPU clock cycle, = 2.0 I
CPU clock cycle, = 1.0 I
Now,
CPU time for each can be calculated as:
CPU time, T =
Thus B is faster than A
Now,
Performance of B is 1.33 times that of A