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kow [346]
3 years ago
6

Tell me something stupid stupidest wins brainliest ​

Advanced Placement (AP)
2 answers:
Andre45 [30]3 years ago
8 0

Answer: I ate poop

Explanation: it was disgusting

andrew11 [14]3 years ago
5 0

Answer:

once i listened to my subs to do a challenge.

Explanation:

it was stupid.

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18. Pollution or waste that is generated from a business is called a:]
Elan Coil [88]

Pollution or waste that is generated from a business is called a waste stream.


Hope this helps :)

5 0
3 years ago
Riddle ---<br><br>Get more crowded never loud <br>what is it ? <br>​
bonufazy [111]

A superposition principle is something that allows a sound to be more crowded with sound waves, but not louder.

We can arrive at this answer because:

  • The superposition principle refers to the joining of many sound waves being emitted at the same time and coming together to form the sound.
  • These waves do not affect each other, but add up, creating a deeper, more intense sound.

As an example, we can use a stadium full of fans, the more crowded the more intense the fans' screams will be, but not louder, as the same waves will be emitted.

More information:

brainly.com/question/1171688

7 0
3 years ago
Which best describes the purpose of this document?
Svetach [21]
<span>It shows how much a person earned, and how much was withheld in taxes.</span>
7 0
3 years ago
Read 2 more answers
Where is on place the main topic should never be?
Elenna [48]
I would believe the conclusion or the plot. I'm not certain so I could be wrong.
8 0
3 years ago
Read 2 more answers
Huge help needed ! im lost and need an explanation to the correct answer.
Semmy [17]

Answer:

m<MON = 100°

Explanation:

Given:

Area of shaded sector LOM = 2π cm²

NL = 6 cm

Required:

m<MON

Solution:

m<MON = 180° - m<LOM (angles in a straight line)

We don't know m<LOM. Therefore, let's find m<LOM.

Area of a sector = θ/360 × πr²

Area of sector LOM = 2π cm²

r = 3 cm

θ = m<LOM = ?

Plug in the values

2π = m<LOM/360 × π × 3²

2π = m<LOM/360 × 9π

2π = m<LOM × 9π/360

2π = m<LOM × π/40

Multiply both sides by 40

2π × 40 = m<LOM × π

80π = m<LOM × π

Divide both sides by π

80π/π = m<LOM

80 = m<LOM

m<LOM = 80°

✔️m<MON = 180° - m<LOM (angles in a straight line)

Substitute

m<MON = 180° - 80°

m<MON = 100°

3 0
3 years ago
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