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3 years ago

Use the diagrams below to find the lengths of the missing sides. Figures in each diagram are similar.

Mathematics

2 answers:

lawyer [7]3 years ago

7 0

Answer:

Step-by-step explanation:

The two triangles are similar

so the equation is

$\frac{12}{18} = \frac{4}{x}$

$12x = 72$

$x = \frac{72}{12}$

$x = 6$

Novosadov [1.4K]3 years ago

6 0

12x=17 hope it help ✌

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mr. Williams and mrs.sims drove 380 miles for a school conference. Mrs.sims drove 55% of the miles. What fraction of miles did m

lisov135 [29]

So 55% is really 55/100
You take 100 - 55 to find how much Mr. Williams drove
100 - 55 = 45

So Mr. Williams drove 45/100 of the miles
Simplified is 9/20 of the miles

6 0

3 years ago

Read 2 more answers

PLEASE HELPPPPP!!!! DUE VERY SOON!!!!

REY [17]

Answer:

-1

-4

Step-by-step explanation:

7 0

3 years ago

Rebecca has $128 to spend. She

kobusy [5.1K]

Answer:

12.5x =10x+10

12.50x=x10+10

subtract 10x from both sides

2.5x=10

divide by 2.5

x=4

5 0

2 years ago

Solve for y: x + 2y = -8 y=-1/2x+4 y=-1/2x-4 y=-2x - 4 y=1/2x-4

adelina 88 [10]

Answer:

x + 2y = -8 = y = -4 - 1/2x

y= -1/2x + 4 = y = 4

y= -1/2x - 4 = y = -4

y=-2x - 4 = y = -4

y=1/2x-4 = y = -4

Step-by-step explanation:

(x + 2y = -8 = y = -4 - 1/2x)

$x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\$

4 0

2 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

3 years ago