Answer:
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Answer: The required derivative is 
Step-by-step explanation:
Since we have given that
![y=\ln[x(2x+3)^2]](https://tex.z-dn.net/?f=y%3D%5Cln%5Bx%282x%2B3%29%5E2%5D)
Differentiating log function w.r.t. x, we get that
![\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5Bx%27%282x%2B3%29%5E2%2B%282x%2B3%29%5E2%27x%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5B%282x%2B3%29%5E2%2B2x%282x%2B3%29%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B4x%5E2%2B9%2B12x%2B4x%5E2%2B6x%7D%7Bx%282x%2B3%29%5E2%7D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B8x%5E2%2B18x%2B9%7D%7Bx%282x%2B3%29%5E2%7D)
Hence, the required derivative is
On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.
From the question it follows that line MK bisects angle ∠JKL into ∠JKM & ∠MKL where M is the point in the interior of ∠JKL.
Therefore, as we have given m∠JKL = 84 & m∠MKL = 42
and we have to find m∠JKM , we will simply write the equation as follow
m∠JKL = m∠JKM + m∠MKL
Inserting values we get,
84 = m∠JKM + 42
m∠JKM = 42
Hence, angle m∠JKM of the triangle ΔJKL is 42.
Learn more about questions related to triangles and their angles here
brainly.com/question/13273388
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Answer:
Pedro: 1481 Base hits
Ricky: 1198 Base hits
Step-by-step explanation:
First, take the total amount of base hits last season 2679, then subtract how many more Pedro has 283.
2679 - 283 = 2396 now divide the sum in half 2396 ÷ 2 = 1198 that gives you how many each player has, you're then going to add the amount that you took off to only Pedras total since he had 283 more
Pedro: 1198 + 283 = 1481
Ricky: 1198
I'd say A. 8000, because you'd get the most answers and the biggest variety in answers for a more accurate sample.
