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katen-ka-za [31]
3 years ago
8

Dexter wrote checks and made the deposits shown in his check registry. What was the change in his balance after these transactio

ns?
A. -$105
B. -$51
C. $337
D. $623

Mathematics
2 answers:
8090 [49]3 years ago
8 0

Answer:

-51

Step-by-step explanation:

-85

+211

-147

+75

-105

=-51

LUCKY_DIMON [66]3 years ago
6 0
-51
Hope its help for u
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If a set of data has mean 60 and variance 9 then it's coefficient of variation is
loris [4]
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4 0
4 years ago
Read 2 more answers
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
3 years ago
Consider the tangent line to the curve y = 6 sin(x) at the point (π/6, 3). (a) Find a unit vector that is parallel to the tangen
mojhsa [17]

Answer:

y=\frac{\pi }{6}+5.196(x-3)

Step-by-step explanation:

We have given the equation y = 6 sin (x)

On differentiating both side \frac{dy}{dx}=m=6cosx

As it passes through the point (\frac{\pi }{6},3)

So \frac{dy}{dx}=6cos\frac{\pi }{6}=5.196

Now the unit vector is parallel to the tangent so m will be 5.196

This passes through the point (\frac{\pi }{6},3)

So unit vector will be y-\frac{\pi }{6}=5.196(x-3)

y=\frac{\pi }{6}+5.196(x-3)

5 0
3 years ago
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