Write an algebraic expression that has three terms. Two of the terms should be variable terms, and one of the terms should be th
1 answer:
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The rate a which the surface area, S, decreases is
The surface area is
S = 4πr²
where r = the radius at time t.
Therefore
When r = 3 cm, obtain
![\frac{dr}{dt}]_{r=3} = - \frac{1}{3} \, cm/s](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdr%7D%7Bdt%7D%5D_%7Br%3D3%7D%20%3D%20-%20%5Cfrac%7B1%7D%7B3%7D%20%5C%2C%20cm%2Fs%20%20)
Answer: -1/3 cm/s (or -0.333 cm/s)
The surface area is
S = 4πr²
where r = the radius at time t.
Therefore
When r = 3 cm, obtain
Answer: -1/3 cm/s (or -0.333 cm/s)
Answer:
5
Step-by-step explanation:
The complex number 4 + 2i on the complex plane has coordinates (4,2) and the complex number 7 - 2i has coordinates (7,-2). Thus, the length of a segment in the complex plane with endpoints at 4 + 2i and 7 – 2i is
cos θ =
cos ∠N =
∠N = cos⁻¹
∠N = 60.65°
Answer: 61°