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Mashcka [7]
3 years ago
15

What is the volume of a cone(in cubic inches) with a radius of 3 inches and a height of 6 inches? Use 3.14 for PI. Round your an

swer to the nearest hundredth.
Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

56.52

Step-by-step explanation:

volume formula of cone-v=(1)/(3)\pi r^(2)h

v=(1)/(3) (3.14) (3)^(2) (6)

v=(1)/(3) (3.14) (9) (6)

v=(1)/(3) (169.56)

v=169.56 ÷ 3

v=56.52

plz mark brainliest

let me know if yall need  help with som else :)

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Determine if the two triangles are congruent. If they are State how you know. NO LINKS!!!​
miv72 [106K]

Problem 25

These triangles are congruent.

The reasoning is the AAS congruence theorem. We have two pairs of congruent angles, as shown by the arc markings, and a pair of congruent sides. The sides are <u>not</u> between the angles. That means AAS is slightly different from ASA. The order matters.

=====================================================

Problem 26

The triangles are <u>not</u> congruent

Why not? Well it all comes down to the angle placement. For the triangle on the right side, the arc is between the shared segment and the segment with the double tickmarks. The other arc is not in the proper corresponding location to be able to use SAS. It would need to be adjacent to the arc on the right for us to use SAS.

If it's hard to visualize what I mean, refer to the diagram below.

=====================================================

Problem 27

The triangles are <u>congruent</u> by <u>SAS</u>

The angles aren't marked, but recall that vertical angles are always congruent. So you could add in angle markers if you wanted, to help complete the diagram. The tickmarks of course tell us which segments are the same length. The angles are between the segments.

====================================================

Problem 28

The triangles are <u>congruent</u> by <u>SSS</u>

Like before, the tickmarks tell us which sides are the same length. So the tickmarks say that we have two pairs of congruent sides. The overlapping sides or shared sides are the third pair of congruent segments. So in reality, we have three pairs of congruent sides. It might help to break up the figure into two separate triangles.

3 0
3 years ago
The edge of a cube was found to be 30 cm with a possible error in measurement of 0.2 cm. Use differentials to estimate the maxim
rjkz [21]

Answer:

Maximum volume error = ±540 cm³

Relative error = 0.02

Percentage error = 2%

Step-by-step explanation:

Relative error : The ratio of volume error to the total volume.

Percentage error: The product of relative error and 100.

The volume of a cube is = side^3

v =x³

Differentiate with respect to x

\frac{dv}{dx} = 3x^2

\Rightarrow dv = 3x^2 dx

Here are x = 30 cm and dx= ±0.2 cm

∴ dv = 3×(30 cm)² (±0.2 cm)

      =±540 cm³

The volume of the cube = 30³ cm ³ = 27,000 cm³

Then the relative error

=\frac{dv}{v}

=\frac{540 cm^3}{27,000 cm^3}

= 0.02.

The percentage error

= (0.02×100)

=2%

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3 years ago
The physician writes an order for 250 mg of a medication for a patient weighing 168 pounds The label on the vial states 100 mg p
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5 ml / 2.5 ml = 2
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Where does -1/2 go on the number line​
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Answer:

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Step-by-step explanation:

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