Answer:
124679 111269 134788
Step-by-step explanation:
this is the answer
Answer:
The additive property of equality.
Step-by-step explanation:
36 is added to both sides of the equation.
T = 6 [h]
s = 340 [mi]
v=s/t=340/6=56.7 [mi/h]
Answer C.
Answer:
![\large\boxed{1.\ (4)^{-3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B1.%5C%20%284%29%5E%7B-3x%5E2%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B3x%5E2%7D%7D)
![\large\boxed{2.\ ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B2.%5C%20ab%5E%7B-3x%7D%3Da%5Cleft%28%5Cdfrac%7B1%7D%7Bb%7D%5Cright%29%5E%7B3x%7D%3Da%5Cleft%5B%5Cleft%28%5Cdfrac%7B1%7D%7Bb%7D%5Cright%29%5E3%5Cright%5D%5Ex%7D)
Step-by-step explanation:
![Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\------------\\\\(4)^{-3x^2}=\left[(4)^{-1}\right]^{3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}](https://tex.z-dn.net/?f=Use%3A%5C%20a%5E%7B-n%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7Ba%7D%5Cright%29%5En%5C%5C------------%5C%5C%5C%5C%284%29%5E%7B-3x%5E2%7D%3D%5Cleft%5B%284%29%5E%7B-1%7D%5Cright%5D%5E%7B3x%5E2%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B3x%5E2%7D)
![Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\ and\ (a^n)^m=a^{nm}\\--------------------\\\\ab^{-3x}=a\cdot b^{-3x}=a\left[(b)^{-1}\right]^{3x}=a\left(\dfrac{1}{b}\right)^{3x}\\\\ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x](https://tex.z-dn.net/?f=Use%3A%5C%20a%5E%7B-n%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7Ba%7D%5Cright%29%5En%5C%20and%5C%20%28a%5En%29%5Em%3Da%5E%7Bnm%7D%5C%5C--------------------%5C%5C%5C%5Cab%5E%7B-3x%7D%3Da%5Ccdot%20b%5E%7B-3x%7D%3Da%5Cleft%5B%28b%29%5E%7B-1%7D%5Cright%5D%5E%7B3x%7D%3Da%5Cleft%28%5Cdfrac%7B1%7D%7Bb%7D%5Cright%29%5E%7B3x%7D%5C%5C%5C%5Cab%5E%7B-3x%7D%3Da%5Cleft%28%5Cdfrac%7B1%7D%7Bb%7D%5Cright%29%5E%7B3x%7D%3Da%5Cleft%5B%5Cleft%28%5Cdfrac%7B1%7D%7Bb%7D%5Cright%29%5E3%5Cright%5D%5Ex)
Answer: Option 'A' is correct.
Step-by-step explanation :
Since we have given that
Number of medals = 2
Number of runners = 8
We need to find the number of ways to award the medals.
We would use "fundamental theorem of counting" to find the number of ways.
So, number of ways is given by
8 × 7 = 56
Hence, option 'A' is correct.