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3 years ago

A local college charges a 9% fee on all late registrations. How much is the fee on a late registration of $155

Mathematics

1 answer:

Deffense [45]3 years ago

8 0

Answer:

13.95

Step-by-step explanation:

9% of 155

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624,612 rounded to the nearest hundred is

Dimas [21]

Answer:

624 600

Step-by-step explanation:

624 <u>6</u>12

you have to concentrate at the 1 because because it's at the tens place, if the 1 is not greater than 5 you don't have to do anything. you just have to remove the two numbers before the the number 6 and you so it automatically should be 624 600.

To round a number to the nearest hundredth , look at the next place value to the right (the tens this time). Same deal: If it's 4 or less, just remove all the digits to the right. If it's 5 or greater, add 1 to the digit in the hundredths place, and then remove all the digits to the right.

3 0

3 years ago

The price of a climbing trip to Mount Kilimanjaro includes an initial fee plus a constant fee per meter.

KatRina [158]

Answer:

Step-by-step explanation:

It's $3.90 for every 30 meters. Or $0.13 for every meter.

3 0

3 years ago

How much can this container hold?

nydimaria [60]

Answer:

225 in.^3

Step-by-step explanation:

You need to find the volume of the container.

The container has the shape of a rectangular prism.

volume = length * width * height

volume = 5 in. * 4.5 in. * 10 in.

volume = 225 in.^3

6 0

3 years ago

A square field had 3 m added to its length ad 2 m added to its width. The field then had an area of 90 m squared. Find the lengt

pogonyaev

Answer:

The length of a side of the original field = 7 m.

Step-by-step explanation:

Here, the initial field is in form of a square.

Let us assume the side of the original square field = k meters

Now, the new length of the field = ( k + 3) m

The new width of the field = ( k + 2) m

So, the new field is now a rectangle with area = 90 sq. m

AREA OF A RECTANGLE = LENGTH x WIDTH

Here, the area of the new field = New length x new width

= ( k + 3) x ( k + 2)

$90 = ( k + 3) \times ( k + 2)\\\implies k^2 + 2k + 3k + 6 = 90\\or, k^2 + 5 k - 84 = 0\\\implies k^2 + 12k - 7k -84 = 0\\or, k (k+12) -7(k+12) = 0\\\implies (k+12)(k-7) = 0$

⇒ either (k +12) = 0 ⇒ k = -12

or, ( k-7) = 0 ⇒ k = 7

But, here k = SIDE OF A FIELD, and it CANNOT be negative.

⇒ k = 7

Hence, the length of a side of the original field = 7 m.

4 0

3 years ago

A jelly bean is 5 grams heavy and a tree is 20 meters tall

Finger [1]

9.945*10^30 Kg - 1.7901*10^32 Kg
This is on average what the mass of a black hole.

8 0

3 years ago