Question

7 times the sum of a squared and b minus 4 times the sum of a squared and b

Answer 1

Let's solve this problem step by step.

First. The sum of a squared and b

$a^2+b$

Second. 7 times the sum of a squared and b

$7(a^2+b)$

Third. 4 times the sum of a squared and b

$4(a^2+b)$

Finally. 7 times the sum of a squared and b minus 4 times the sum of a squared and b

$7(a^2+b)-4(a^2+b)$

And this is:

$\boxed{7(a^2+b)-4(a^2+b)=3(a^2+b)}$

Answer 2

(7•((a^2)+b))-(4•((a^2)+b))