Answer:
Step-by-step explanation:
put x=7 in the given equation
which is true .
∴ x=7 is a solution of the given eq.
now put x=4 in the given eq.
which is not true.
∴x=4 is an extraneous solution.
<h3>Answer:</h3><h3>f(x)=5x^(4)+3x^(2)+6x^(-1)-3 =20x^3+6x-6/x2</h3><h3>f(x)=(7)/(8)x^(3)+2x^(5)-6x+17 = f=16x5+7x3−48x+136/8x</h3><h3>f(x)=5\sqrt(3+4x)= \frac{10}{\sqrt{3+4x}}</h3><h3>f(x)=(1)/(x^(2))+(1)/(x)-12x^(2)= -\frac{2}{x^3}-\frac{1}{x^2}-24x</h3><h3>1.yes,2.yes,3.no,4.yes hope this helps</h3>
Answer:
D
Step-by-step explanation:
This can be broken up into √3 / √25, since √25 = 5 the final answer is √3/5.