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Maru [420]
2 years ago
9

What is the area of the figure to the nearest hundredth renter the answer in the box 2yd 4yd

Mathematics
1 answer:
Norma-Jean [14]2 years ago
3 0

Answer:

9.57 yd squared

Step-by-step explanation:

we can divide this figure into two shapes:  a rectangle and a semi-circle

since we know the length and width of the rectangle, all we ahve to do is multiply them together to find the area: <u>8 yd squared</u>

for the semi-circle, we know the area is \frac{\\\pi r^2}{2\\}

raduis is half the diameter so 1 yd

\frac{3.14(1)^2}{2}

\frac{3.14}{2}<u />

<u>1.57 yd squared</u>

lastly, add the area of the two figures together 8+1.57

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f(x) = y

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Please help me I need this ASAP (5.6) times 1/8
Triss [41]

Answer:

7/10 or 0.7

Step-by-step explanation:

The first step that you need to do is to convert 5.6 to a fraction. 5.6 can be rewritten as \frac{56}{10}, which is equal to \frac{28}{5}.To multiply two fractions together, you simply need to multiply together the numerators and then the denominators. \frac{28}{5}\cdot\frac{1}{8}=\frac{28}{40}=\frac{7}{10}=0.7. Hope this helps!

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3 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

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sp2606 [1]

Answer:

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Step-by-step explanation:

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