Change the x and y
Then solve for y
X= 8y+1
Subtract 1 from both sides
X-1=8y
Divide by 8
X-1 /8 = y
The answer to your question is b.
Answer: three pieces.
The piece of wood is 6/8 inches long - this fraction can be simplified to 3/4 by dividing both the numerator and denominator by 2.
Thus, he cuts a piece of wood that is 3/4 inches long into 1/4 inch pieces.
1 goes into 3 three times, so the piece of wood can be cut into three 1/4-inch pieces.
Answer:
There were 6 benches in park 1 and 18 benches in park 2.
Step-by-step explanation:
Let x be the no of benches in Park 1 and y in park 2.
Given that there are 12 more benches in park 2 than 1
Writing this in equation form, we have y = x+12 ... i
Next is if 2 benches were transferred from park 2 to park 1, then we have
x+2 in park 1 and y-2 in park 2.
Given that y-2 = twice that of x+2
Or y-2 = 2x+4 ... ii
Rewrite by adding 2 to both sides of equation ii.
y = 2x+6 ... iii
i-iii gives 0 = -x+6
Or x =6
Substitute in i, to have y = 6+12 = 18
Verify:
Original benches 6 and 18.
18 = 6+12 hence I condition is satisfied
18-2 = 2(6+2)
II is also satisfied.
0.15c>10+0.10c
0.05c>10
c>200
