Answer:
a type nut is 10 pounds
a different one is 14 pounds
Step-by-step explanation:
let a type of the nut be represented by t
Let a different one be represented by d
a type of nut cost $7 per pound
a different one cost $4.20 per pound
The cost of the mixture for 24 pounds = 5.37 * 24
= $128.88
t + d = 24 ........(1)
7t + 4.2d = 128.88 ..........(2)
From equation (1), t = 24 - d
Put t = 24 - d in equation 2
7(24 - d) + 4.2d = 128.88
168 - 7d + 4.2d = 128.88
168 - 2.8d = 128.88
-2.8d = 128.88 - 168
-2.8d = -39.12
d = -39.12 / -2.8
d= 13.97
d = 14 pounds
t = 24 - d
t = 24 - 14
t = 10 pounds
A type nut is 10 pounds. A different one is 14 pounds
Gretchen will earn $48 from mowing in 4 hours
Data
- Amount earned on each lawn = $12
- Number of hours mowing = 4 hours
<h3>What is Rate</h3>
This is the measure of one unit against another unit. An example of this is speed which is the rate of distance covered to time.
In this case, she mows 1 lawn in each hour and earns $12 on each.
To calculate for 4 hours
She earns $48 from mowing 4 lawns
learn more on rates here;
brainly.com/question/8728504
<u>Answer:</u>
<h2>SA = 84 ft²</h2>
<u>Explanation:</u>
SA = the area of one side of the pyramid times 4 + the area of the base of the pyramid
Area of a triangle = (height × base)/2
Area of a sqaure = lenght²
given:
h = 4 ft | b = 6 ft | l = 6 ft
SA = 4(h×b×1/2) + l²
SA = 4(4×6×1/2) + 6²
SA = 4×12 + 36
SA = 48 + 36
SA = 84 ft²
The answer would be 30%
Explanation~
Well, you would have to add 27 and 23 first since, it says, “What percentage of the twelfth grade students have more than one college in mind” then, you’d have to figure out the percentage from there. And the percentage would be, 29.4117647059% of 170, round that to the nearest percent and it’s 30 I’m pretty sure.
Answer:
The factors of x^2+3x-4 are (x-1)(x+4) ....
Step-by-step explanation:
We have to find the factors of x^2+3x-4
As we know that this is a quadratic equation.
So we have to find the roots first.
The roots are -1 and 4.
Now completing the quadratic formula using the roots we have :
x^2+4x-x-4
Make a pair of first two terms and last two terms:
(x^2+4x)-(x+4)
Now take out the common from each pair:
x(x+4)-1(x+4)
(x-1)(x+4)
Thus the factors of x^2+3x-4 are (x-1)(x+4) ....
