Answer: The withholding tax rate changes depending on how much the person is paid.
There is no single rate that applies to every person for every pay period if hours worked or tips/commissions paid are different every week.
Step-by-step explanation:
Above the examples chart there is a list of $-amounts "Over ..... But not over" To the right of that, you have a list of a base amount withheld and a % rate to be applied. Those are the % rates you are looking for.
Once you have a given "gross pay" to work with, you find out where that falls into the amounts given, select the base and %, then follow the steps as you see in the examples in the chart.
Answer:
A. 33
B. k=32
C. 1
D. ![\pm 1,\ \pm 2,\ \pm 4](https://tex.z-dn.net/?f=%5Cpm%201%2C%5C%20%5Cpm%202%2C%5C%20%5Cpm%204)
E. ![B=-2,\ D=5](https://tex.z-dn.net/?f=B%3D-2%2C%5C%20D%3D5)
Step-by-step explanation:
In all parts for the quadratic equation
use Vieta's formulas
![x_1+x_2=-\dfrac{b}{a},\\ \\x_1\cdot x_2=\dfrac{c}{a},](https://tex.z-dn.net/?f=x_1%2Bx_2%3D-%5Cdfrac%7Bb%7D%7Ba%7D%2C%5C%5C%20%5C%5Cx_1%5Ccdot%20x_2%3D%5Cdfrac%7Bc%7D%7Ba%7D%2C)
where
are the roots of the quadratic equation.
A. For the equation ![x^2-5x-4=0,](https://tex.z-dn.net/?f=x%5E2-5x-4%3D0%2C)
![x_1+x_2=5,\\ \\x_1\cdot x_2=-4.](https://tex.z-dn.net/?f=x_1%2Bx_2%3D5%2C%5C%5C%20%5C%5Cx_1%5Ccdot%20x_2%3D-4.)
Then
![(x_1+x_2)^2=x_1^2+2x_1\cdot x_2+x_2^2,\\ \\5^2=x_1^2+x_2^2+2\cdot (-4),\\ \\x_1^2+x_2^2=25+8=33.](https://tex.z-dn.net/?f=%28x_1%2Bx_2%29%5E2%3Dx_1%5E2%2B2x_1%5Ccdot%20x_2%2Bx_2%5E2%2C%5C%5C%20%5C%5C5%5E2%3Dx_1%5E2%2Bx_2%5E2%2B2%5Ccdot%20%28-4%29%2C%5C%5C%20%5C%5Cx_1%5E2%2Bx_2%5E2%3D25%2B8%3D33.)
B. One of the roots of
is twice the other root, then
By the Vieta's formulas,
![x_1+x_2=3x_1=-12,\\ \\x_1\cdot x_2=2x_1^2=k.](https://tex.z-dn.net/?f=x_1%2Bx_2%3D3x_1%3D-12%2C%5C%5C%20%5C%5Cx_1%5Ccdot%20x_2%3D2x_1%5E2%3Dk.)
Then
and ![k=2x_1^2=2\cdot (-4)^2=2\cdot 16=32.](https://tex.z-dn.net/?f=k%3D2x_1%5E2%3D2%5Ccdot%20%28-4%29%5E2%3D2%5Ccdot%2016%3D32.)
C. The sum of the roots of the quadratic
is ![-\dfrac{b}{c}=-\dfrac{-4}{4}=1.](https://tex.z-dn.net/?f=-%5Cdfrac%7Bb%7D%7Bc%7D%3D-%5Cdfrac%7B-4%7D%7B4%7D%3D1.)
D. Note that
![(Ax+B)(Cx+D)=ACx^2+x(AD+BC)+BD,](https://tex.z-dn.net/?f=%28Ax%2BB%29%28Cx%2BD%29%3DACx%5E2%2Bx%28AD%2BBC%29%2BBD%2C)
then
If
are integers, then you should check ![A=\pm 1,\ \pm 2,\ \pm 4.](https://tex.z-dn.net/?f=A%3D%5Cpm%201%2C%5C%20%5Cpm%202%2C%5C%20%5Cpm%204.)
E. Consider
Note that
![x_1+x_2=\dfrac{1}{3},\\ \\x_1\cdot x_2=-\dfrac{10}{3}.](https://tex.z-dn.net/?f=x_1%2Bx_2%3D%5Cdfrac%7B1%7D%7B3%7D%2C%5C%5C%20%5C%5Cx_1%5Ccdot%20x_2%3D-%5Cdfrac%7B10%7D%7B3%7D.)
Then
![x_1=2,\ x_2=-\dfrac{5}{3}.](https://tex.z-dn.net/?f=x_1%3D2%2C%5C%20x_2%3D-%5Cdfrac%7B5%7D%7B3%7D.)
Then
hence ![B=-2,\ D=5.](https://tex.z-dn.net/?f=B%3D-2%2C%5C%20D%3D5.)
Answer:
True
Step-by-step explanation:
The Interquartile Range (IQR) is a more robust measure of variability because it excludes outliers from the distribution. Due to this fact, the IQR works with only 50% of the central data excluding the outlying values in the data set from its calculation.
The variance is affected by outliers, and the Range is way more affected by only the first and the last observation.
So, yes the IQR is the least influenced. Therefore, a more robust measure of variability.
Answer:
Monica has 3 more pieces of gold than silver after she cut all her wire
Step-by-step explanation:
Total length of gold wire Monica has= 7.68 meters
Length of each piece Monica wants to cut the wire into = 0.96 meters
Total number of pieces she can cut =
= 8 pieces of gold wire
Total length of gold wire Monica has = 7.45 meters
Length of each piece Monica wants to cut the wire into = 1.49 meters
Total number of pieces she can cut =
=5 pieces silver wire
Gold wire pieces= 8
Silver wire pieces= 5
Difference in the number of pieces = ![8-5=3](https://tex.z-dn.net/?f=8-5%3D3)
Monica has 3 more pieces of gold than silver after she cut all her wire
Answer:
Apples
Step-by-step explanation:
To find the cost per pound you need to divide the amount of money by the amount of apples: $6/5 which equals $1.2 or $1.20