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3 years ago

What is point N in this triangle called?

Mathematics

1 answer:

N76 [4]3 years ago

4 0

Point N is called the centroid of the triangle.

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Ingram called Verizon to argue about his bill. He was paying $95.26 monthly but he argued the new bill down to $78.17. What was

kumpel [21]

Answer:

Step-by-step explanation:

((95.26 - 78.17) / 78.17)x100

21.86260714% percentage decrease

The phone call was worth his time

7 0

3 years ago

Read 2 more answers

Help pls reallyyyyyyyyyyyyyyyyyy

Ivan

Answer:

Step-by-step explanation:

j=6

k=4

Rewrite the equation. So let's do that-

2.5(6*4)/6

6 and the other 6 cancel out so we are left with 2.5*4

Which is then equal to 10.

By the way, whenever you see the same number in a division problem on the numerator and denominator, just cancel them out because if you still did 2.5(6*4)/6, you would still get 10. I was just simplifying it!

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3 years ago

Please help.I need all comparing parts, corresponding parts, and the last question in the problem.

mamaluj [8]

Shift left 4 units
rotate clockwise 270 degrees about the origin
not sure about the statement though

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3 years ago

Which ratios of side lengths are equal to tan (a) ?

Eddi Din [679]

Answer:

$tan(\alpha)=\frac{opposite}{adjacent}$

Step-by-step explanation:

$tan(\alpha)=\frac{opposite}{adjacent}$

4 0

2 years ago

Read 2 more answers

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

3 years ago