Answer:
240°
Step-by-step explanation:
Draw a line EF perpendicular to AB and CD passing through M
In △BME
∠BME+∠MBE+∠BEM=180∘ (Angle sum proprerty)
∠BME+35∘+90∘=180∘∠BME=180∘−125∘∠BME=45∘
In △DMF
∠DMF+∠MDF+∠MFD=180∘ (Angle sum property )
∠DMF+75∘+90∘=180∘∠DMF=180∘−165∘∠DMF=15∘
x=∠DMF+∠BME+∠EMF
x=15∘+45∘+180∘x=240∘
Step-by-step explanation:
a power supply, a load suited to the power supply, and wiring as a conductor
3x + 11y = 4
2x + 6y = 0
I got
15/2, -5/4
Answer - 4 classes
117 ÷ 29 = 4.03...
That is the answer. hope this helps.
