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aleksley [76]
3 years ago
7

What is the product? 3x(-6 -11 -14 -9)

Mathematics
1 answer:
Fofino [41]3 years ago
7 0

Answer:

The product is -120

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S is the midpoint of RT. R has the coordinates (-6, -1), and S has coordinates (-1, 1). Find the coordinates of T.
bekas [8.4K]
If the distance from R to S is only half then the other half is S to T. The distance between R and S is (5,2). that should give you the answer
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3 years ago
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exercise alone. Two methods of collecting data have been proposed. Method I: Recruit volunteers who are willing to participate.
aniked [119]

Answer:

I) If method I is used, population of generalization will include all those people who may have varying exercising habits or routines.  They may or may not have a regular excersing habit.  In his case sample is taken from a more diverse population

II) Population of generalization will include people who will have similar excersing routines and habits if method II is used since sample is choosen from a specific population

Step-by-step explanation:

past excercising habits may affect the change in intensity to a targeted excersise in different manner. So in method I a greater diversity is included and result of excersing with or without a trainer will account for greater number of variables than method II.

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3 years ago
Find the prime factorization: 49 i am stuck
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8 0
3 years ago
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PLEASE HELP Which line has an x-intercept of -5 and a y-intercept of 3?
anygoal [31]

Answer:

the first answer or a

Step-by-step explanation:

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5 0
3 years ago
HELP ASAP
astra-53 [7]

Answer:

Step-by-step explanation:

We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:

Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:

5^2 = 3^2 + x^2

x = 4

The radius is 4 + 1 cm = 5 cm

So the area of the circle is A = pi*r^2

A = 3.14 * (5)^2  

A = 25pi cm^2

To solve for the area of the shaded region:

Ashaded = Acircle - Atriangles

we need to solve for the area of the triangles:

A = 1/2 *b*h

A = 1/2 *6 * 5

A = 15 cm^2

Atriangles = 2 * 15  

Atriangles = 30 cm^2

Ashaded = 25pi - 30

8 0
2 years ago
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