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dolphi86 [110]
2 years ago
10

15 pt = _______ qt

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

4. 7 1/2 is Answer

Step-by-step explanation:

I hope it's helpful!

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I have the same problem. I think it is 4.
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2 years ago
How do I solve please help me out
adoni [48]

You by combing like terms

8 0
3 years ago
Find the product:<br><br> (r+2)(r-5)(r-2)(r+5)<br><br> Please show all steps.<br><br> 15 points.
Virty [35]

Hello from MrBillDoesMath!

Answer:

r^4- 29r^2 + 100

Discussion:

Rearrange the terms in the product as follows:

(r+2)(r-2) *  (r-5)(r+5)  =

(r^2 - 4) * (r^2-25) =

f^4 - (25+4)r^2 + 4*25 =

r^4- 29r^2 + 100

Thank you,

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7 0
3 years ago
Read 2 more answers
A loaf of sandwich bread contains 24 slices. Which of these tables correctly shows the ratios of different numbers of loaves of
noname [10]

Answer:

15

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5 0
2 years ago
A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample
suter [353]

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender               | 0-30| 30-60| 60-90| 90+       Totals

Male                    | 23    |    35   |   76    |  46        180

<u> Female               |   31   |    42   |   46    |  16         135    </u>

<u>Totals                    54         77        122    62          315  </u>

<u />

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females)   =  Total of (30-6)/ (total )* females

                                                                      = ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²=  (33-42)²/33= 2.455  ( for the single value of E2,2=33)

Expected for the (30-60 box for males)   =  Total of (30-6)/ (total )* males

                                                                      = ( 77/315)180= 44

χ²=  (44-42)²/44= 0.09

The critical region is  χ² (0.05) 3 ≥  χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.  

6 0
2 years ago
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