7x - 44 = 4x + 4
Add both sides 44
7x - 44 + 44 = 4x + 4 + 44
7x = 4x + 48
Subtract both sides 4x
7x - 4x = 4x - 4x + 48
3x = 48
Divide both sides by 3
3x ÷ 3 = 48 ÷ 3
<h2>x = 16 </h2>
______________________________
Suppose that the angle between 39 and 4x + 4 is t degrees as you know they make a straight line together thus :
39 + t + 4x + 4 = 180
39 + t + 4(16) + 4 = 180
39 + t + 64 + 4 = 180
39 + t + 68 = 180
t + 107 = 180
Subtract both sides 107
t + 107 - 107 = 180 - 107
<h2>t = 73 </h2>
_____________________________
8y - 43 = 4x + 4 + t
8y - 43 = 4(16) + 4 + 73
8y - 43 = 64 + 4 + 73
8y - 43 = 68 + 73
8y - 43 = 141
Add both sides 43
8y - 43 + 43 = 141 + 43
8y = 184
Divide both sides by 8
8y ÷ 8 = 184 ÷ 8
<h2>y = 23 </h2>
Cost depends on the class size , so
cost is the dependent variable and class size is the independent.
The answer i came up with is : (4b-7x) (a+2)
Answer:
A
Step-by-step explanation:
she borrowed 20 and gave back some of it, x is the rest she needs to give back
