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olasank [31]
3 years ago
15

I need help with this question I’ll give 15 points

Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0

Answer:

the (5 x 2)

Step-by-step explanation:

weeeeeb [17]3 years ago
3 0

Answer:

Calculating (5 x 2) violates the order of operations

Step-by-step explanation:

According to the order of operations, multiplies all have equal priority. Therefore, they must be evaluated left to right, not right to left. Evaluating (5 x 2) first is incorrect, and instead (9 x 5) should be calculated first.

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10. Using Base 10 blocks, show & explain how to divide 35 (3 longs and 5 units) by 5. (DRAW
Lina20 [59]
Each long piece is composed of 10 unit blocks (smallest squares). 

The three long pieces means that they make up 3*10 = 30 units so far. Add on the 5 extra units and we have 30+5 = 35 units total

If we have 35 squares, then we can group them up into groups of 5. Doing so will leave you with 7 groups. 
4 0
3 years ago
Help I would love to give you a thanks
WARRIOR [948]

Answer:

Formula

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
At its peak, an online shopping site was selling about 420420 items per second. At this rate, how many items would it sell in 30
EastWind [94]

Answer:

756.000.

Step-by-step explanation:

That is 420 * 1800

= 756.000

3 0
3 years ago
Ruby has a monthly salary of $1,800 and also earns 6% commission on her sales. If Ruby had $37,000 in sales last month, what wer
Dovator [93]

Answer:

D 4,020

Step-by-step explanation:

$37,000(.06) = $2,220

$2,220 + $1,800 = $4,020

have a good day!!

5 0
3 years ago
Read 2 more answers
A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

3 0
3 years ago
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