Let the equal sides of the isosceles Δ ABC be x.
Given that the perimeter of Δ ABC = 50m.
Therefore, 2x + AC = 50 --- (1)
It is also given that the perimeter of Δ ABD = 40m.
Therefore, x + BD + AD = 40
BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.
So AD = CD.
Or, AD =
AC
Therefore, 
Multiply both sides by 2.
2x + 2BD + AC = 80
From (1), 2x + AC = 50.
Therefore, 2BD + 50 = 80
2BD = 80 - 50
2BD = 30
BD = 15m.
Answer:
The equation would be:

In the attachment!!!
<em>Hope this helps!!!</em>
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Using derivatives, it is found that the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
The acceleration is the <u>derivative of the velocity</u>, given by change in velocity divided by change in time, that is:

In this problem:
- The change in time for objects C and T is the same.
- The <u>change in velocity for object C is greater</u>, thus, it has a greater acceleration, and the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
A similar problem is given at brainly.com/question/14516604