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3 years ago

8

Nigel wants to average 85% on his four tests. He got 77%, 89%, 78% on his first three tests. What does he need to get on his las

t test to average 85%?

1 answer:

Arte-miy333 [17]3 years ago

4 0

Answer:

He needs to get 96%

Step-by-step explanation:

Add 96 89 77 and 78 together and divide by 4, it should be 85

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Solve −3x2 − 4x − 4 = 0

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This is a quadratic formula with a general form of a²x + bx + c = 0. For quadratic equations, we can solve for its two roots using the quadratic formula shown in the attached picture.

a = -3
b = -4
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x = [-(-4) + √(-4)² - 4(-3)(-4)]/2(-3) = <em>2 + √-32/2</em>
x = [-(-4) - √(-4)² - 4(-3)(-4)]/2(-3) =<em> 2 - √-32/2</em>

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Are you trying to simply the equation if so x = 6

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3 years ago

60 in<br> 63 in<br> What is the length of the hypotenuse?<br> inches<br> Submit

saveliy_v [14]

Answer:

assuming 60 and 63 are the side lengths

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Step-by-step explanation:

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2 years ago

Two equivalent equations of the line in point slope form for (-4,8) and (0,5)

34kurt

Answer:

Equation of line 1 is 3 X - 4 Y = 20

Equation of line 2 is 3 X + 4 Y = 20

Step-by-step explanation:

Given co ordinates of points as,

( -4 , 8) and (0 , 5)

From the given two points we can determine the slop of a line

I. e slop (m) = $\frac{(y2 - y1)}{(x2 - x1)}$

Or, m = $\frac{(5 - 8)}{(0 + 4)}$

So, m = $\frac{(-3)}{(4)}$

Now equations of line can be written as ,

Y - y1 = m ( X - x1)

<u>At points ( -4 , 8)</u>

Y - 8 = $\frac{(-3)}{(4)}$ (X + 4)

So , Equation of line 1 is 3 X - 4 Y = 20

<u>Again with points ( 0 , 5)</u>

Y - 5 = $\frac{(-3)}{(4)}$ ( X - 0)

So, Equation of line 2 is 3 X + 4 Y = 20

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3 years ago

Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t

andrew11 [14]

Answer:

a) X Freq. Rel Freq.

__________________________

0 7 (7/58) = 0.121

1 10 (10/58)=0.172

2 13 (13/58) =0.224

3 14 (14/58)=0.241

4 6 (6/58)=0.103

5 3 (3/58)=0.052

6 3 (3/58)=0.052

7 1 (1/58) =0.017

8 1 (1/58)=0.017

_________________________

Total 58 1.00

b) $\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862$

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2 2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3 3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X Freq. Rel Freq.

__________________________

0 7 (7/58) = 0.121

1 10 (10/58)=0.172

2 13 (13/58) =0.224

3 14 (14/58)=0.241

4 6 (6/58)=0.103

5 3 (3/58)=0.052

6 3 (3/58)=0.052

7 1 (1/58) =0.017

8 1 (1/58)=0.017

_________________________

Total 58 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

$\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862$

4 0

3 years ago