Use photo math for this :)
Let
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so

where
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

where
denotes the CDF of
, and
denotes the inverse CDF. We have

Similarly, because 20% of students obtain less than 40 marks, we have

so that

Then
are such that


and we find

Answer:
4 / 5
Step-by-step explanation:
From the image attached, Line BA is divided into a total of 5 equal proportions (or intervals). Point P is placed at the 4th proportion of the divided line, also the distance between point P and point A is 1 propotion. The ratio in which point P divides the line BA is given as:
Ratio = BP : PA = 4 : 1
Ratio = 4 : 1
The part to whole ratio If point p partitions line BA = BP / BA = 4 / 5
Part to whole ratio = 4/5
Sqrt14 = 3.74165
smallest integer above = 4
Answer:
w=6x+1.25
Step-by-step explanation: