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3 years ago

Simplify as much as possible (and only have positive exponents)

Mathematics

1 answer:

svetoff [14.1K]3 years ago

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If there are x teams in a sports league, and all the teams play each other twice, a total of N(x) games are played, where N

Elena-2011 [213]

Answer:

It will cost $700 to play the entire schedule.

Step-by-step explanation:

Given : $N(x)=x^2-x$

To Find : A softball league has 5 teams, each of which play the others twice. If the league pays $35 per game, how much will it cost to play the entire schedule?

Solution:

Equation for total no. of games when all the teams play each other twice is $N(x)=x^2-x$

Now we are given that A softball league has 5 teams, each of which play the others twice.

So, Substitute x = 5 in the given equation

$N(x)=5^2-5$

$N(x)=20$

So, The total no. of games = 20

Cost for 1 game = $35

So, cost for 20 games = $35 \times 20 = 700$

Hence it will cost $700 to play the entire schedule.

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3 years ago

Jamie can paint a wall in 54 minutes Together Connie and Jamie can paint the same wall in 36 minutes How long would it take Conn

Zina [86]

Answer:

The answer is 108

Step-by-step explanation:

I did this for my exam got 100

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3 years ago

What do you think the answer is?

Katen [24]

Answer:

i think the answer is c

Step-by-step explanation:

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3 years ago

Three years ago, Jolene bought $550 worth of stock in a software company. Since then the value of her purchase has been increasi

KengaRu [80]

Answer:

Hence the the value of stock after three years worth $734.44

Step-by-step explanation:

According to question ,

Jolene bought three years ago, stock in a company worth = $550

The value has been increase after three year at rate of = 10.12 %

So,

The value after three years can be written as

Final value = initial value $( 1 +\frac{Rate}{100})^{Time}$

Or, Final value = $550 $( 1 +\frac{10.12}{100})^{3}$

Or, Final value = $550 (1.102)³

Or, Final value = $550 × 1335

I.e final value = $734.44

Hence the the value of stock after three years worth $734.44 Answer

4 0

3 years ago

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4

lesya692 [45]

The empirical rule says that roughly 99.7% of the population is within 3 standard deviations of the mean.

Start at the center 60 which is the mean. Add on 3 standard deviations

60 + 3*4.5 = 73.5

and subtract off 3 standard deviations from the mean

60 - 3*4.5 = 46.5

So roughly 99.7% of the population of cattle has horn lengths between 46.5 inches and 73.5 inches

<h3>Answer: Choice D. 46.5 in - 73.5 in</h3>

4 0

3 years ago

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