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2 years ago

7

At Saturday night’s football game there were 18 less fans than half the fans at Friday night’s game. There were “x” fans at Frid

ay’s game. Write an expression to represent the number of fans at Saturday’s game.

1 answer:

Valentin [98]2 years ago

7 0

X divided by 2 take away 18 hope it helps.

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(8b^2/3*9t^3/5)(8b^5/3*9t^3/5)

erma4kov [3.2K]

Answer:

5,184•b•t^6/5

Step-by-step explanation:

Here, we want to multiply the expressions

According to indices law, if we have same bases, we add up the exponents

Thus, we have that;

8 *8b^(2/3+5/3) * 9 * 9 * t^(3/5+3/5)

= 64 * b * 81 * t^6/5

= 5,184bt^6/5

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2 years ago

What is compatible number to find two estimates that the quotient is between 1624÷3

Vladimir [108]

1500÷3 =500

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2 years ago

Can anyone help??

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2 years ago

tatiyna

IT DOES NOT MATTER YOU WILL NOT BE ABLE TO SOLVE THIS QUESTION
YOU WOULD GET 5x = 2 + 3x^2 AND YOU WOULD STILL NOT BE ABLE TO SOLVE YOU COULD GET 3x^2 = 2 + 5x AND YOU COULD NOT SOLVE.
THE REASON WHY IS BECAUSE YOU HAVE TO HAVE THE SAME X TO ADD THEM OR MINUS THEM< WHICH IN THIS CASE ONE IS REGULAR BUT THE OTHER IS SQUARED. AND ALSO THE TWO NEEDS SOMEONE TO GO WITH< BUT THE IS ONLY ONE OF HIS TYPE SO HE CAN'T.
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2 years ago

The distances male long jumpers for State College jump are approximately normal with a mean of 263 inches and a standard deviati

Effectus [21]

Answer:

His jump was of 272.45 inches

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 263, \sigma = 14$

75th percentile

X when Z has a pvalue of 0.75. So X when Z = 0.675

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 263}{14}$

$X - 263 = 14*0.675$

$X = 272.45$

His jump was of 272.45 inches

7 0

2 years ago

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