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denis-greek [22]
3 years ago
9

I pleased anyone to help me please​

Mathematics
2 answers:
Gennadij [26K]3 years ago
3 0

Answer:

The first one (90, 90) is supplimentary, the next two (54, 36. and 45, 45) are complimentary, and the last two are supplimentary.

Step-by-step explanation:

A complimentary angle is two angles that add up to 90, and supplimentary is two angles that add up to 180! :)

Flauer [41]3 years ago
3 0

Answer:

1st picture at the top would be a supplementary angle because a supplementary angles always add to 180 degrees.

the 54 and 36 one is a complementary angle

the 45 and 45 would be complementary angle

the last two on the bottom would both be supplementary angles.

High hopes-

Barry

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Sixty percent of the customers who go to Sears Auto Center for tires buy four tires and 22% buy two tires. Moreover, 14% buy few
Bezzdna [24]

Answer:

There is a 4% probability that a customer buys three tires.

Step-by-step explanation:

We have those following percentages

60% buy four tires. This is also the probability that someone buys four tires.

22% buy two tires

14% buy fewer than two tires(one or none).

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The sum of the percentages must be 100%.

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8 0
3 years ago
I need help with this ASAP and can you explain so i can understand?!
Elanso [62]

Answer:

Adult tickets sold =  225

Student Tickets sold =  375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

Total tickets sold = 600

So, we can write: x+y = 600

Total money collected = 3037.50

Cost of 1 Adult ticket = $6.00

Cost of one Student ticket = $4.50

So, we can write: 6x+4.5y=3037.50

Now, we get a system of equations, that if solved we can find values of x and y

Let:

x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)

We can solve using substitution method.

Finding value of x from eq(1) and putting it in eq(2)

We\:have\\x+y=600\\x=600-y

Put in eq(2)

6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375

So, we get value of y = 375

Now put value of y in eq(1) to find value of x

x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225

So, we get value of x = 225

The Tickets sold will be:

Adult tickets sold = x = 225

Student Tickets sold = y = 375

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2 years ago
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Answer:

The answer is C. The translation of a line is a pair of parallel lines.

Step-by-step explanation:

A, B, and D are true. C is <em>not</em> true, and therefore the correct answer.

5 0
2 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cfrak%7B%20%5Corange%7B%20Question%7D%7D" id="TexFormula1" title=" \large\frak{ \
SVEN [57.7K]

Answer:

\boxed{\sf distance \: between \:  the \: objects \: \: is  \: 2.5 \: cm}

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

A = G \cdot  \frac{m_1.m_2}{ {d}^{2} }

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

<em>Given:</em>

A1 = 2 units

d1= 5 cm

A2 = 8 units

<em>To find:</em>

Distance of separation when the force of attraction is 8 units d2 = ?

<em>Solution:</em>

Substituting the given values in above at each point,

A_1 = G \cdot  \frac{m_1.m_2}{ {d_1}^{2} }  \\ 2 = G \cdot  \frac{m_1.m_2}{ {5}^{2} }  \\  \sf similarly  \: at \:  second \:  point \:  of  \: attraction \\  A_2 = G \cdot  \frac{m_1.m_2}{ {d_2}^{2} }  \\ 8 = G \cdot  \frac{m_1.m_2}{ {d_2}^{2} }  \\  \sf \: \: dividing \:  both  \: of \:  the \:  equation \\  \frac{2}{8}  =  \frac{G \cdot  \frac{m_1.m_2}{ {5}^{2} }}{G \cdot  \frac{m_1.m_2}{ {d_2}^{2} } }  \\  \sf \: G \: m_1 and \: m_2  \: are \:   \: constant  \: hence  \\ \sf  they \:  can  \: be  \: cancelled \:  out  \\  \frac{2}{8}  =  \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } }  \\  \sf rearranging \: above \: equation \\  \frac{1}{4}  =  \frac{{d_2}^{2} }{ {5}^{2} }  \\ {d_2}^{2}  =   \frac{ {5}^{2} }{4 }  \\ {d_2}^{2}  =  \frac{25}{4}   \\ {d_2}^{2}  = 6.25 \\  \sqrt{{d_2}^{2} }  =  \sqrt{6.25}  \\  \boxed{ \sf{d_2} = 2.5 \: cm}

<em>Answer:</em><em> </em><em>the distance between the two </em><em>objects </em><em>is </em><em>2</em><em>.</em><em>5</em><em> </em><em>cm</em><em>, if the attraction between them is 8 </em><em>units.</em>

<em><u>Learn more about universal law of gravitation here brainly.com/question/27244479</u></em>

<em>Thanks </em><em>for </em><em>joining </em><em>brainly </em><em>community</em><em>!</em>

7 0
2 years ago
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