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inysia [295]
3 years ago
6

Do cells without spindle fibre continue to grow into abnormal cells?

Biology
1 answer:
solniwko [45]3 years ago
3 0
What are the five phases of the cell cycle? ... What would happen if the cell did not have spindle fibers? Without spindle fibers, the sister chromatids would not separate, and each daughter cell would not receive a complete set of genes. Compare cell division in prokaryotic cells with cell division in eukaryotic cells.
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To report a code for hepatic capillariasis, the coder would report _____.
vekshin1

The icd-10-CM codes is International Classification of Diseases, Tenth Revision, Clinical Modification.

The icd-10-CM is used for the clinical manifestation of the diseases or the abnormalities detected during the treatment procedures. These codes are used for the reimbursement purpose of the treatment or the diagnostics provided.

B83.8 is a code for the hepatic capillariasis. The code B83.8 is used for billable diagnostics in the case of Helminths infection.

So, the given blank can be filled with B83.8.

8 0
3 years ago
A student isolates, purifies, and combines in a test tube a variety of molecules needed for DNA replication. After adding some D
aivan3 [116]

Answer:

DNA ligase

Explanation:

DNA replication is an enzyme mediated, 3-step process during which the DNA molecule produces a copy of itself. The 3 steps involved are as follows;

  • initiation
  • elongation
  • termination

<em>Initiation </em>involves the unwinding of the double helix structure of the DNA using DNA helicase enzyme

<em>Elongation</em> involves binding of RNA primer to the DNA strands and addition of bases to the primer<em> </em>to elongate the new chains. Bases are added to the leading strand continuously while the lagging strand is replicated in short segments (okazaki segments).

<em>Termination</em> involves the unbinding of RNA primer and substitution of its bases by DNA bases. The Okazaki fragments are then joined together using the DNA ligase enzyme.

<em>The short, numerous segments of DNA observed in the mixture is the Okazaki fragments of the lagging strand. This is due to the absence of the enzyme involved in the joining of these fragments.</em>

Hence, the answer is DNA ligase.

4 0
3 years ago
Allosteric proteins and the regulation of metabolic pathways would be expected to be found at ________ and ____________ of metab
scoundrel [369]

Answer:

e) B and C

Explanation:

Allosteric regulation occurs at these points where the concentration of the substrate and/or products is important for the activation and inhibition of the enzyme.

3 0
3 years ago
How much pesticide will each hawk take in compared to each grasshopper?
Leni [432]
On the off chance that rodent nourishes upon grasshopper as in betray grasshoppers are the main source accessible. on the off chance that there is bug spray weight in the field on grasshopper and they are alive that implies they have been uncovered at the sub-deadly level then is devoured by rats which open up in light of the fact that it takes a few grasshoppers every day comparatively the peddle is tainted being top customer it stores more than its supplicate
3 0
3 years ago
Regulatory and basal transcription factors regulate transcription by binding to the promoter.A) True B) False
Licemer1 [7]

Answer:

False

Explanation:

In eukaryotes apart from RNA polymerase, the transcription of genes requires many different proteins called transcription factors. These transcription factors are important to initiate and regulate transcription.

There are two types of transcription factors regulatory and basal transcription factors. Basal transcription factors regulate transcription by binding to a gene promoter and regulatory transcription factor regulates transcription by binding to some regulatory sequences for example enhancers and silencers.  

Therefore only basal transcription factor binds to the promoter for regulating transcription. Therefore the statement is false.

4 0
3 years ago
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