What is the value of 64 ? A. 4 B. 21 1/3 C. 8 D. 2

nikklg [1K]

Answer:

KJFJDSKLJDKLFJDSKJDSFKDMF;DS MDF NM FDSF DS FSDFSD FJJKFSDN DSF DSJFJDSFDNFDFNDMFDNSAFJASNF,MASFNAS2`1849 ,MNFNMADBFASBJ2L31U93O2KQN 4Y72 7IW4N LOOK THIS UP TO GET ANSWERS

Step-by-step explanation:

4 0

3 years ago

Find the supplementary angle.

AleksAgata [21]

Answer:

x=146 degrees

Step-by-step explanation:

A supplementary angle is the conrisponding angle that adds to the other angle so it is 180. So 180-34= 146

4 0

3 years ago

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Question Help Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a

koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So $\mu = 5656, \sigma = 333.3$

(a) What proportion of light bulbs will last more than 6262 hours?

The pvalue of the z-score of $X = 6262$ is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.