Answer:
Approximately 6.4
Step-by-step explanation:
We can use the pythagorean thereom here, that tells us (a^2)+(b^2)=c^2. C is the hypotenuse, the side opposite from the right angle, while a and b are the other sides. We can insert 5 and 4 as a and b, and solve for c
:(5^2)+(4^2)=c^2
:25+16=c^2
:41=c^2
:sqrt(41)=6.4=c (We square rooted both sides. 6.4 is only rounded to the nearest hundredths place.) Hope this helps!
Answer:
A) ERROR
B) ∠C = 26°
Step-by-step explanation:
Houston, We have a problem!!! too much information
If we had a legit triangle, the law of sines would hold
19/sin138 = 8/sin20
28.395 = 23.390
as this is NOT an equality, the triangle does not exist as described.
IF it did, we'd get different results depending on which set we used
∠F = 180 - 138 - 20 = 22°
Law of sines
19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>
or
8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>
If we attempt to use Law of cosines
DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>
so really none is correct because we attempt to use trig calculations to a non-triangle.
12) AC² = 15² + 19² - 2(15)(19)cos120
AC = 29.51270...
29.51270 / sin120 = 15/sinC
C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>
Answer:
No, I'm not old enough to work at taco bell yet
Step-by-step explanation:
Answer:
Step-by-step explanation:
The first step will be to make y the subject of the formula, by multiplying both sides of the equation by -1.
y = x - 1
This is simply the equation of a line with a slope of 1 and y-intercept (0,-1)
To determine the three points that solve the equation, we can let x be;
0, 1, 2
When x =0, y = 0-1 = -1
When x = 1, y = 1-1 = 0
When x = 2, y = 2 - 1 = 1
Therefore, we have the following three sets of points that can be used to graph the given linear equation;
(0, -1)
(1, 0)
(2, 1)
Find the attached for the graph
9514 1404 393
Answer:
24
Step-by-step explanation:
The number of permutations of 4 items is 4! = 24.
math, maht, mtah, mtha, mhat, mhta,
amth, amht, atmh, athm, ahmt, ahtm,
tmah, tmha, tamh, tahm, thma, tham,
hmat, hmta, hamt, hatm, htma, htam
