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sukhopar [10]
3 years ago
11

6-2x=6x-10x+14 what is the value of x

Mathematics
2 answers:
alukav5142 [94]3 years ago
8 0
6 - 2x = 6x - 10x + 14
-2x - 6x + 10x = 14 - 6
2x = 8
x = 4
kakasveta [241]3 years ago
7 0
X=4
Subtract six from both sides
Add 10x to both sides
Then you have 8x=6x+8
Then subtract 6x on both sides
And you have 2x equals 8
Divide both sides by 2 and you get
X=4
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I don't understand this. Please help!:::: Provide an answer for a, b, c, and d.
OleMash [197]
Answer for part A is  \angle A \cong \angle D which in English means "angle A is congruent to angle D"

The reason why we know that angle A and angle D are congruent is because they are both right angles. By the right angle congruence theorem (the reason just below the blank for part A), we can say that angle A = angle D. They are both 90 degree angles. 

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Answer for the blank in part B is "Given" without quotation marks of course. This is the first "given" while the second given is coming up in part C

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For part C, the other given is \angle C \cong \angle F so that's what will go in the blank. It may seem silly, but all we're doing is repeating verbatim what is given to us. With any proof, you always start with what you are given and somehow connect it with what you're trying to prove

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Finally, the answer for the blank in part D is "AAS Congruence Theorem" (without quotes)

The AAS congruence theorem allows us to prove two triangles congruent if we know if two pairs of angles are congruent plus if we know two sides are congruent as well.

The angle portions are covered by part A and part C. The side portions are part B's territory. Combining A, B, & C allows us to use the AAS theorem

Note: It is NOT the ASA theorem because the two angles do not sandwich the sides. In other words, the side AB is not between the two angles A and C. Similarly, DE is not between the two angles D and F. The order is very important as ASA is slightly different than AAS. 

8 0
4 years ago
2. Marquan sells pretzels at Auntie Anne and earns $15 per hour,
Andre45 [30]

dollars per hour = salary

a

dollars per hours multiplied with hours worked (h) = total earnings

b

15 x 2 = 30

15 x 3 = 45

15 x 5 = 75

(h)

6 0
3 years ago
Plz
allsm [11]
Top box is 2x
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4 0
3 years ago
Please help me solve this question. Will make you the
zmey [24]

The relation you have shown is not a function.

In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.

One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.

6 0
3 years ago
A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 ​respon
Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14​% chose chocolate​ pie, and the margin of error was given as plus or minus ±3 percentage points. 

The pivotal quantity for the confidence interval for the population proportion is given by;

                            P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who chose chocolate​ pie = 14%

            n = sample of adults = 500

            p = true proportion

Now, the 99% confidence interval for p =  \hat p \pm Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.03 for 99% interval.

<u>So, 99% confidence interval for p</u>  =  0.14 \pm2.5758  \times \sqrt{\frac{0.14(1-0.14)}{500} }

                                                        = [0.14 - 0.03 , 0.14 + 0.03]

                                                        = [0.11 , 0.17]

Similarly, <u>80% confidence interval for p</u>  =  0.14 \pm 1.2816  \times \sqrt{\frac{0.14(1-0.14)}{500} }

Here, \alpha = 20% so  (\frac{\alpha}{2}) = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.02 for 80% interval.

So, <u>80% confidence interval for p</u>  =  [0.14 - 0.02 , 0.14 + 0.02]

                                                           =  [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0
4 years ago
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