All categories

3 years ago

-2x + 3x - 5 = 6 - 21 FIND x

Mathematics

1 answer:

trasher [3.6K]3 years ago

5 0

Before we do any solving, we need to simplify both sides.

On the left, we can simplify -2x + 3x - 5 to x - 5.

On the right, we can simplify 6 - 21 to -16.

So we have x - 5 = -16.

Solving from here, we add 5 to both sides to get x = -11.

You might be interested in

The perimeter of a rectangular field is 328 yards. If the length of the field is 89 yards, what is its width?

miv72 [106K]

Set up an equation based on the information given

$89 + 89 + x + x = 328$

Combine like terms

$89 + 89 = 178$

$x + x = 2x$

$2x + 178 = 328$

Solve

$2x + 178 = 328$

$328 - 178 = 150$

$2x = 150$

$x = 75$

Answer

The width of the rectangular field is 75 yards.

7 0

3 years ago

Question 11 plz, really need help

madam [21]

Answer:

ummm hold on im trying to figure it out sorry might take long

7 0

3 years ago

Read 2 more answers

Which expression is equivalent to

lutik1710 [3]

Answer:

$\frac{\sqrt[4]{3x^2} }{2y}$

Step-by-step explanation:

We can simplify the expression under the root first.

Remember to use $\frac{a^x}{a^y}=a^{x-y}$

Thus, we have:

$\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}$

We know 4th root can be written as "to the power 1/4th". Then we can use the property $(ab)^{x}=a^x b^x$

So we have:

$\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}$

Option D is right.

8 0

4 years ago

A conjecture and the flowchart proof used to prove the conjecture are shown.

viva [34]

The required proof of parallelogram is given below,

What is parallelogram?

A parallelogram is a straightforward quadrilateral with two sets of parallel sides in Euclidean geometry. The opposing or confronting sides and the opposing angles in a parallelogram are of equal length.

For a parallelogram, opposite sides are always equal and parallel.
So for the given parallelogram, we get AD = BC and AD and BC are parallel.

AD and BC is parallel and DC is common side, therefore, $\angle 1 = \angle 3$ ......(1)

Given $\angle 3 = \angle 2$ .......(2)

Therefore, from condition (1) and (2), we get

$\angle 1 = \angle 2$

If $\angle 1 = \angle 2$ then DC bisects the angle $\angle ADE$ . [Proved]

To learn more about parallelogram from the given link

brainly.com/question/970600

#SPJ1

4 0

1 year ago

How do you get the perimeter of a triangle, all side are 28 cm?

Alisiya [41]

Perimeter of the triangle, a+b+c

In this case, a=b=c=28

So, perimeter would be 28*3 = 84 cm

7 0

3 years ago