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kirill115 [55]
3 years ago
14

Which of the following pairs of numbers contains like fractions?

Mathematics
1 answer:
Hatshy [7]3 years ago
6 0
D if you multiply 5/6 by 2/2 you get 10/12. So they are like fractions
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I will give extra points please help
weqwewe [10]

Answer:

7

Step-by-step explanation:

<u>3 </u>+ 4 = 7.

So, therefor, x = 3

6 0
3 years ago
Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x+3) and (x+12)
Alex Ar [27]

Answer:

A product of factors is zero if and only if one or more of the factors is zero.  That is, if ab = 0, then either a = 0 or b = 0 (or both).

Hence (x+3)(x+12) = 0 only if (x+3) = 0 or (x+12) = 0 or both.  (x+3) = 0 when x = 3.(x+12) = 0 when x = 12.

Hence the values of x that make (x+3)(x+12) = 0 are x = 3 and x = 12.

3 0
3 years ago
Read 2 more answers
Sergio makes belts in his garage.He makes a certain number of belts for every hour he works.what is the missing value in the tab
aleksklad [387]
Is 12 Because the pattern is 2+1=3; 4+2=6;
6+3=9; 8+4=12 and 10+5=15
8 0
3 years ago
The data below indicate the time (in seconds) that it takes 25 separate employees to complete a certain task. hw1_q5.csva) What
IgorC [24]

Answer:

Explained below.

Step-by-step explanation:

Consider the data provided.

(a)

Compute the mean of the data in seconds as follows:

Mean =AVERAGE(array)

         = 225.280 seconds

(b)

Compute the median of the data in seconds as follows:

Median =QUARTILE.EXC(array,2)

            = 229 seconds

(c)

Compute the variance of the data in seconds as follows:

Variance =VAR.S(array)

              = 1148.043 seconds

(d)

Compute the standard deviation of the data in seconds as follows:

Standard deviation =STDEV.S(F2:F26)

                              = 33.883 seconds.

(e)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

            = 3.755 minutes.

(f)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

            = 3.817 minutes

(g)

Compute the variance of the data in minutes as follows:

Variance =VAR.S(array)

              = 0.319 minutes

(h)

Compute the standard deviation of the data in minutes as follows:

Standard deviation =STDEV.S(F2:F26)

                              = 0.565 minutes.

3 0
3 years ago
If you help me I'll mark you branliest and give five star rating​
Olenka [21]

Answer:

See explanation for answer, hope it helps

Step-by-step explanation:

Toss; 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Total number of heads so far; 1, 1, 1, 1, 2, 3, 4, 4, 4, 5

Relative Frequency of heads so far;

\frac{1}{1} = 1.0 = 100%

\frac{1}{2} = 0.5 = 50%

\frac{1}{3} = 0.33 = 33%

\frac{1}{4} = 0.25 = 25%

\frac{2}{5} = 0.4 = 40%

\frac{3}{6} = 0.5 = 50%

\frac{4}{7} = 0.57 = 57%

\frac{4}{8} = 0.5 = 50%

\frac{4}{9} = 0.44 = 44%

\frac{5}{10} = 0.5 = 50%

Total number of tails so far; 0 1, 2, 3, 3, 3, 3, 4, 5, 5

Relative Frequency;

\frac{0}{1} = 0 = 0%

\frac{1}{2} = 0.5 = 50%

\frac{2}{3} = 0.66 = 66%

\frac{3}{4} = 0.75 = 75%

\frac{3}{5} = 0.6 = 60%

\frac{3}{6} = 0.5 = 50%

\frac{3}{7} = 0.42 = 42%

\frac{4}{8} = 0.5 = 50%

\frac{5}{9} = 0.55 = 55%

\frac{5}{10} = 0.5 = 50%

8 0
2 years ago
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