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marin [14]
2 years ago
14

Pls help pls i need help

Mathematics
1 answer:
UkoKoshka [18]2 years ago
7 0

Answer:

ok

Step-by-step explanation:

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First of all, you can simplify the 4 at the numerator and the 14 at the denominator (they're both multiple of 2):

\dfrac{4}{14\sqrt{2}} = \dfrac{2\cdot 2}{2\cdot 7\cdot\sqrt{2}} = \dfrac{2}{7\sqrt{2}}

Now, rationalize a denominator means that you have to get rid of the square root, in order to have an integer denominator.

To do so, remember that you can always multiply any number by 1 without changing its value, and you can always think of 1 as a fraction where numerator and denominator are equal:

\dfrac{2}{7\sqrt{2}} = \dfrac{2}{7\sqrt{2}}\cdot 1 = \dfrac{2}{7\sqrt{2}} \cdot \dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{2\sqrt{2}}{7\cdot 2} = \dfrac{\sqrt{2}}{7}

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3 years ago
Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.
KatRina [158]
AB = AU + UB = 20x + 108 + 273 = 20x + 381

\cfrac{AU}{AB} =\cfrac{UV}{BC}    \\  \\  \cfrac{20x+108}{20x+381} =\cfrac{444}{703}   \\  \\ 703(20x+108)=444(20x+381)\\\\14060x+75924=8880x+169164 \\  \\ 14060x-8880x = 169164 - 75924 \\  \\ 5180x = 93240 \\  \\ x=93240/5180 \\  \\ x=18
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Simplify sin^2y/sec^2 y−1 to a single trigonometric function
liubo4ka [24]

Answer:

\frac{ { \sin}^{2} y}{ { \sec}^{2}y - 1 }  =  { \cos }^{2} y

Step-by-step explanation:

We know that { \tan }^{2} y =  { \sec }^{2} y - 1

Also , { \tan}^{2} y =   \frac{ { \sin }^{2} y}{ { \cos }^{2}y }

So ,

\frac{ { \sin }^{2}y }{ { \sec }^{2}y - 1 }  =  \frac{ { \sin}^{2} y}{ { \tan }^{2} y}  =  \frac{ { \sin }^{2}y }{ \frac{ { \sin}^{2} y}{ { \cos}^{2}y } }  =  { \cos }^{2} y

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2 years ago
How to name a angle in 4 different ways?<br> First answer and correct answer gets to be brainliest!
likoan [24]

Hey there!

  • 4 ways to name angles

⇒ Use the vertex as the middle letter, and the point from each side (<ABC or <CBA)

⇒ Use the vertex only (<B)

⇒ Use a number (<1)

  • Classify angles according to their measure.

⇒ Acute angle: less than 90°

⇒ Right angle: exactly 90°

⇒ Obtuse angle: between 90° and 180°

⇒ Straight angle: exactly 180°

Thank you,

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See the attachment for a visual!

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2 years ago
Anyone, I need help... Just answer the 6 (c)....and also proper working.☺️
Ainat [17]

Answer:

(i) The area of the rabbit cage when the width is 5.2 m is 81.5 m²

(ii) The area of the rabbit cage if Wilson has 40 meters of wire mesh is 75 m²

Step-by-step explanation:

(i) The given relation of the area, A to the width P of the rabbit cage is A = 3·p²

The graph of the function between the values of 0 and 6 inclusive is found as follows;

A,              3·p²

0,               0

1,                1

2,               12

3,               27

4,               48

5,               75

6,               108

Please find attached the graph of A to 3·p²

From the graph, we have when the the width, p, of the rabbit cage = 5.2, the area, A ≈ 81.5 m²

The area of the rabbit cage when the width is 5.2 m = 81.5 m²

(ii) Also from the graph given that the total wire mess with Wilson = 40 meters, we have;

The formula for the perimeter of the cage = The formula for the perimeter of a rectangle = 2×length + 2×width

The formula for the perimeter of the cage = 2×3×p + 2× p = 8·p

Where the total length of the wire mesh available = 40 meters for the cage

The 40 meters of wire mesh will be used round the perimeter of the cage

∴ 40 m. = 8·p

p = 40/8 = 5 m.

At p = 5 m. the area is given as A = 75 m².

Therefore, the area of the rabbit cage if Wilson has 40 meters of wire mesh = 75 m².

5 0
3 years ago
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