Answer:
Part A)
Part B)
Step-by-step explanation:
Par A) Write an equation that relates the distance D this car travels in T hours
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or
The speed is a proportional relationship between the distance and the time
Let
D ----> the distance in miles
T ----> the time in hours
so
In this problem the constant of proportionality k represent the speed of the car in miles per hour
we have

substitute
Part B) Use the equation to find the distance the car travels between 3:30 p.m. and 5:00 p.m
we know that
The time between 3:30 p.m. and 5:00 p.m is equal to
5:00 p.m-3:30 p.m=1.5 hours
so
For T=1.5 h
substitute in the equation and solve for D
Answer:
C.
Step-by-step explanation:
Answer: (10x + 30)
Step-by-step explanation:
1. combine like terms. -4x + 3x = -x
2. you can’t have a negative x, so you would multiply the equation (-x+3) by -1, to get (x-3).
3. (x-3)(10)... 10 • x = 10x, 10 • 3 = 30.
4. put them together, answer would be 10x + 30.
Answer:
Step-by-step explanation:
<em>See the drawing attached</em>
<h3>Given</h3>
- C is midpoint of AB
- B is between A and D
- AD = 15
- BD = 7
- Find CD
<h3>Solution</h3>
- CD = CB + BD =
- 1/2AB + BD =
- 1/2(AD - BD) + BD =
- 1/2(15 - 7) + 7 =
- 1/2(8) + 7 =
- 4 + 7 =
- 11
Answer:
3√6
Step-by-step explanation:
tan60=opp/adj
opp(d)=tan60*3√2=√3*3√2=3√6