Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Free points rights anyways can someone help me with this answer
A 85-kg is clown is fired from rest out of 480-kg cannon. If the clowns speed is 18 meters per second after the firing, then what is the recoil speed of the cannon? (Round your answer to the nearest tenth)
6+z=10x-2
6+z=-20
Z=-20-6
Z=-26
Hope this helps!
Have you tried using
M
A
T
H
W
A
Y
Answer:
I think it would be c 160
Step-by-step explanation:
